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anonymous

  • one year ago

find the Riemann sum for f(x)=x^2+x over the interval(0,8),where x0=0,x1=1,X2=3,X3=7,X4=8,and where c1=1,c2=2,c3=5 and c4=8

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  1. Loser66
    • one year ago
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    What are c's??

  2. Loser66
    • one year ago
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    center??

  3. Loser66
    • one year ago
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    \(\sum_{[x_n-x_{n-1}]} f(x) dx\) now, at c1= 1, f(1) = 1^2 +1 =2 and \(\triangle x= 1-0 =1\) hence, the first term is 2*1 the second term: at c2= 2, f(2) =2^2+2 = 6 and \(\triangle x = 3-1=2\) hence the second term is 6*2 =12 do the same with the third term and the fourth term add them together. done

  4. Loser66
    • one year ago
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    |dw:1437947344077:dw|

  5. Loser66
    • one year ago
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    |dw:1437947415085:dw|

  6. Loser66
    • one year ago
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    |dw:1437947484448:dw|

  7. Loser66
    • one year ago
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    do the same with the fourth term, then add them together.

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