## anonymous one year ago find the Riemann sum for f(x)=x^2+x over the interval(0,8),where x0=0,x1=1,X2=3,X3=7,X4=8,and where c1=1,c2=2,c3=5 and c4=8

1. Loser66

What are c's??

2. Loser66

center??

3. Loser66

$$\sum_{[x_n-x_{n-1}]} f(x) dx$$ now, at c1= 1, f(1) = 1^2 +1 =2 and $$\triangle x= 1-0 =1$$ hence, the first term is 2*1 the second term: at c2= 2, f(2) =2^2+2 = 6 and $$\triangle x = 3-1=2$$ hence the second term is 6*2 =12 do the same with the third term and the fourth term add them together. done

4. Loser66

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5. Loser66

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6. Loser66

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7. Loser66

do the same with the fourth term, then add them together.