If c(x) = 4x – 2 and d(x) = x2 + 5x, what is c(d(x))

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If c(x) = 4x – 2 and d(x) = x2 + 5x, what is c(d(x))

Mathematics
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hey you again :D
ello same question :=)
so just do the same thing?

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yes right
but x is already x so would it be 2x^2 + 5x^2 in the D function?
that would be the same so just replace x in c(x) function by d(x)
\[\huge\rm c(\color{ReD}{d(x)}) = c(\color{Red}{x^2+5x}) =4\color{reD}{x}-2\]
so am i just simplifying x^2+5x=4x-2?
no you need to plug x^2+5x into the x c(x^2+5x) is same as c(d(x))
4x -2 ^^^ that x replace by x^2 +5x
ohhh
4x^2 + 3
mhm.. how did you get that ?
4 and x^2 combine then 5-2
remember when multiply same bases we should add their exponents \[\huge\rm x^m \times x^n = x^{m+n}\] and on't forget the parenthesis
it should be like this \[\huge\rm 4(x^2+5x)-2\] distribute parentheses by 4 and then combine like terms
ohh i forgot parentheses
4x2+20x−2??
:=) right

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