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anonymous

  • one year ago

If c(x) = 4x – 2 and d(x) = x2 + 5x, what is c(d(x))

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  1. anonymous
    • one year ago
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    hey you again :D

  2. Nnesha
    • one year ago
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    ello same question :=)

  3. anonymous
    • one year ago
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    so just do the same thing?

  4. Nnesha
    • one year ago
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    yes right

  5. anonymous
    • one year ago
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    but x is already x so would it be 2x^2 + 5x^2 in the D function?

  6. Nnesha
    • one year ago
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    that would be the same so just replace x in c(x) function by d(x)

  7. Nnesha
    • one year ago
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    \[\huge\rm c(\color{ReD}{d(x)}) = c(\color{Red}{x^2+5x}) =4\color{reD}{x}-2\]

  8. anonymous
    • one year ago
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    so am i just simplifying x^2+5x=4x-2?

  9. Nnesha
    • one year ago
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    no you need to plug x^2+5x into the x c(x^2+5x) is same as c(d(x))

  10. Nnesha
    • one year ago
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    4x -2 ^^^ that x replace by x^2 +5x

  11. anonymous
    • one year ago
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    ohhh

  12. anonymous
    • one year ago
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    4x^2 + 3

  13. Nnesha
    • one year ago
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    mhm.. how did you get that ?

  14. anonymous
    • one year ago
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    4 and x^2 combine then 5-2

  15. Nnesha
    • one year ago
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    remember when multiply same bases we should add their exponents \[\huge\rm x^m \times x^n = x^{m+n}\] and on't forget the parenthesis

  16. Nnesha
    • one year ago
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    it should be like this \[\huge\rm 4(x^2+5x)-2\] distribute parentheses by 4 and then combine like terms

  17. anonymous
    • one year ago
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    ohh i forgot parentheses

  18. anonymous
    • one year ago
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    4x2+20x−2??

  19. Nnesha
    • one year ago
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    :=) right

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