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purplemexican
 one year ago
Which values of p and q would make the value of the following expression equal to 29i?
(2 – 5i)(p + q)i
purplemexican
 one year ago
Which values of p and q would make the value of the following expression equal to 29i? (2 – 5i)(p + q)i

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SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0Ok, expand the (25i)(p+q)i and what do you then get?

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1yes in other words multiply out the bracket

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.0its still confusing

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0\(\large\color{black}{ \displaystyle (a+b)(c+d)=ab+ac+bc+bd }\) have you seen anything like this before?

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.0i need to look into which property is which still get them confused

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0\(\large\color{black}{ \displaystyle (2 – 5i)(p + q)=2(p+q)5i(p+q) }\) same way as: \((ab)(C)=a(C)b(C)\)  And therefore: \(\large\color{black}{ \displaystyle (2 – 5i)(p + q)i=2i(p+q)5i^2(p+q) }\) we know \(i^2=1\) because \(i^2=\left(\sqrt{1}\right)^2=1,\) like any \(\left(\sqrt{a}\right)^2=a\) So, \(\large\color{black}{ \displaystyle (2 – 5i)(p + q)i=2i(p+q)5(1)(p+q) }\) \(\large\color{black}{ \displaystyle (2 – 5i)(p + q)i=2i(p+q)+5(p+q) }\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0Now, how would you get 29i in a "a+bi" form? 0+29i and so here we have this form as well 5(p+q) + 2(p+q)i so a=0=5(p+q) bi=29i=2(p+q)i

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0solve the system 0=5(p+q) 29=2(p+q) (> this eq. results after canceling the i's on both sides.)
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