## anonymous one year ago A state vector X for a four-state Markov chain is such that the system is four times as likely to be in state 3 as in 4, is not in state 2, and is in state 1 with probability 0.2. Find the state vector X.

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1. anonymous

The probability of all states add up to $$1$$. Let $$a$$ be the probability of state 4. $0.2 + 0 + 4a + a =1$If you solve for $$a$$, then you can use: $X = \begin{bmatrix}0.2 \\ 0 \\ 4a \\ a\end{bmatrix}$

2. anonymous

There is already an open question that has the same problem as yours. :O

3. anonymous
4. UnkleRhaukus

hmmm