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anonymous

  • one year ago

A state vector X for a four-state Markov chain is such that the system is four times as likely to be in state 3 as in 4, is not in state 2, and is in state 1 with probability 0.2. Find the state vector X.

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  1. anonymous
    • one year ago
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    The probability of all states add up to \(1\). Let \(a\) be the probability of state 4. \[ 0.2 + 0 + 4a + a =1 \]If you solve for \(a\), then you can use: \[ X = \begin{bmatrix}0.2 \\ 0 \\ 4a \\ a\end{bmatrix} \]

  2. anonymous
    • one year ago
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    There is already an open question that has the same problem as yours. :O

  3. anonymous
    • one year ago
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    http://openstudy.com/study#/updates/55b5b91de4b0d48ca8eeed71

  4. UnkleRhaukus
    • one year ago
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    hmmm

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