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Ac3

  • one year ago

Find the area of the region between y=e^X; y=x^(2)+1;x=-1;x=1

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  1. SolomonZelman
    • one year ago
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    maybe y=x²-1 ? because with y=x²+1 u get two different regions

  2. dumbcow
    • one year ago
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    |dw:1437953821025:dw| from -1<x<0 , x^2+1 > e^x \[Area = \int\limits_{-1}^0 (x^2 +1) - e^x\] from 0<x<1, e^x > x^2+1 \[Area = \int\limits_0^1 e^x - (x^2 +1)\]

  3. SolomonZelman
    • one year ago
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    dx's?

  4. SolomonZelman
    • one year ago
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    lol

  5. SolomonZelman
    • one year ago
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    Ac3, are you sure the question is precisely as you stated?

  6. IrishBoy123
    • one year ago
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    yeah!! if you don't put dx at the end, the magic doesn't work :p LOL

  7. Ac3
    • one year ago
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    yea i figured out thanks guys.

  8. Ac3
    • one year ago
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    its' from -1,1 by the way.

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