Ac3
  • Ac3
Find the area of the region between y=(x-2)^2,y=x. The answer is 9/2. I got 6 though.
Calculus1
chestercat
  • chestercat
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Ac3
  • Ac3
did it again and got 7/2
Ac3
  • Ac3
Now I got -9/2 I must have forgotten a negative somewhere or the book is wrong.
IrishBoy123
  • IrishBoy123
area between: \(y=(x-2)^2\) and \(y=x\) \(\large \int_{1}^{4} x - (x-2)^2 \ dx\) it is 9/2

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Ac3
  • Ac3
wait isn't (x-2)^2 greater than x?
anonymous
  • anonymous
|dw:1437967868334:dw|
Ac3
  • Ac3
maybe drawing out the graph would've helped lol thanks guys
Ac3
  • Ac3
Thanks again Irish Boy
IrishBoy123
  • IrishBoy123
yes always draw it
IrishBoy123
  • IrishBoy123
anonymous
  • anonymous
yw

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