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Ac3
 one year ago
Find the area of the region between y=(x2)^2,y=x. The answer is 9/2. I got 6 though.
Ac3
 one year ago
Find the area of the region between y=(x2)^2,y=x. The answer is 9/2. I got 6 though.

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Ac3
 one year ago
Best ResponseYou've already chosen the best response.1Now I got 9/2 I must have forgotten a negative somewhere or the book is wrong.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1area between: \(y=(x2)^2\) and \(y=x\) \(\large \int_{1}^{4} x  (x2)^2 \ dx\) it is 9/2

Ac3
 one year ago
Best ResponseYou've already chosen the best response.1wait isn't (x2)^2 greater than x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1437967868334:dw

Ac3
 one year ago
Best ResponseYou've already chosen the best response.1maybe drawing out the graph would've helped lol thanks guys

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1yes always draw it

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1thanks @surjithayer
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