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Ac3

  • one year ago

Find the area of the region between y=(x-2)^2,y=x. The answer is 9/2. I got 6 though.

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  1. Ac3
    • one year ago
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    did it again and got 7/2

  2. Ac3
    • one year ago
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    Now I got -9/2 I must have forgotten a negative somewhere or the book is wrong.

  3. IrishBoy123
    • one year ago
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    area between: \(y=(x-2)^2\) and \(y=x\) \(\large \int_{1}^{4} x - (x-2)^2 \ dx\) it is 9/2

  4. Ac3
    • one year ago
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    wait isn't (x-2)^2 greater than x?

  5. anonymous
    • one year ago
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    |dw:1437967868334:dw|

  6. Ac3
    • one year ago
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    maybe drawing out the graph would've helped lol thanks guys

  7. Ac3
    • one year ago
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    Thanks again Irish Boy

  8. IrishBoy123
    • one year ago
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    yes always draw it

  9. IrishBoy123
    • one year ago
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    thanks @surjithayer

  10. anonymous
    • one year ago
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    yw

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