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purplemexican

  • one year ago

Using the quadratic formula to solve 2x2 = 4x – 7, what are the values of x?

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  1. LynFran
    • one year ago
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    rewrite the equation to get 2x^2-4x+7=0 where a=2 , b=-4 and c=7 now substitute the values in the quadratic formula \[\frac{ -b \pm \sqrt{(b ^{2}-4ac)} }{ 2a }\]

  2. LynFran
    • one year ago
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    \[\frac{ -(-4)\pm \sqrt{((-4)^{2}-4(2)(7))} }{ 2(2) }\]now simplify...

  3. Purplemexican
    • one year ago
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    its been a while since ive done this and ive lost it

  4. anonymous
    • one year ago
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    Linda I need you for a minute

  5. anonymous
    • one year ago
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    continuing the step: \[\frac{ (4)\pm \sqrt{(16)-(56)} }{ 4 }\]

  6. anonymous
    • one year ago
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    \[\frac{ (4)\pm \sqrt{(-40)} }{ (4) }=\frac{ (4)\pm \sqrt{(40)(-1)} }{ 4 }\]

  7. anonymous
    • one year ago
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    complex numbers: \[\frac{ (4)\pm(\sqrt{40})(\sqrt{-1}) }{ 4 }=\frac{ (4)\pm(\sqrt{40})i }{ 4 }\] :)

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