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- anonymous

Jason has two bags with 6 tiles each. The tiles in each bag are shown below:
Make 6 squares. The squares are numbered sequentially from 1 to 6.
Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 5 from the first bag and an odd tile from the second bag?

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- anonymous

- chestercat

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- Vocaloid

let's break the problem down into smaller pieces
1. what is the probability of drawing a tile numbered 5 from the first bag?

- anonymous

1/6

- Vocaloid

right! now let's move to the next part
2. what is the probability of drawing an odd tile from the bag?

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- anonymous

1/2

- Vocaloid

right! now multiply the two probabilities together
(1/6)*(1/2) = ?

- anonymous

3/6

- Vocaloid

uh, not quite, we need to multiply them together
2*6 = ?

- anonymous

12/36

- anonymous

im so confused

- Vocaloid

not quite, all you need to do is multiply the numerators, then multiply the denominators
hint:
(A/B)*(C/D) = A*C/(B*D)

- Vocaloid

|dw:1437960480314:dw|

- anonymous

3/36

- Vocaloid

right, and 3/36 is also equal to 1/12, which is our answer

- anonymous

thats what ithought but 1/12 was not a choose but 3/36 is thank you

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