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anonymous

  • one year ago

Jason has two bags with 6 tiles each. The tiles in each bag are shown below: Make 6 squares. The squares are numbered sequentially from 1 to 6. Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 5 from the first bag and an odd tile from the second bag?

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  1. Vocaloid
    • one year ago
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    let's break the problem down into smaller pieces 1. what is the probability of drawing a tile numbered 5 from the first bag?

  2. anonymous
    • one year ago
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    1/6

  3. Vocaloid
    • one year ago
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    right! now let's move to the next part 2. what is the probability of drawing an odd tile from the bag?

  4. anonymous
    • one year ago
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    1/2

  5. Vocaloid
    • one year ago
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    right! now multiply the two probabilities together (1/6)*(1/2) = ?

  6. anonymous
    • one year ago
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    3/6

  7. Vocaloid
    • one year ago
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    uh, not quite, we need to multiply them together 2*6 = ?

  8. anonymous
    • one year ago
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    12/36

  9. anonymous
    • one year ago
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    im so confused

  10. Vocaloid
    • one year ago
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    not quite, all you need to do is multiply the numerators, then multiply the denominators hint: (A/B)*(C/D) = A*C/(B*D)

  11. Vocaloid
    • one year ago
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    |dw:1437960480314:dw|

  12. anonymous
    • one year ago
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    3/36

  13. Vocaloid
    • one year ago
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    right, and 3/36 is also equal to 1/12, which is our answer

  14. anonymous
    • one year ago
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    thats what ithought but 1/12 was not a choose but 3/36 is thank you

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