shamallamadingdong
  • shamallamadingdong
Help Plz http://gyazo.com/791ba1e67749d45a03862b429f1570c3
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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shamallamadingdong
  • shamallamadingdong
anonymous
  • anonymous
take the average in each coordinate i.e add them up, divide by two
shamallamadingdong
  • shamallamadingdong
so i would add all the a together ?

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anonymous
  • anonymous
it is \((a,a)\) and \((3a, a)\) right?
anonymous
  • anonymous
first coordinate of the midpoint will be \(\frac{a+3a}{2}\) that is not the final form of course
anonymous
  • anonymous
you got that?
shamallamadingdong
  • shamallamadingdong
kinda
anonymous
  • anonymous
what do you get for \[\huge \frac{a+3a}{2}\]
anonymous
  • anonymous
if it is not clear, let me know and i can show you
shamallamadingdong
  • shamallamadingdong
could i use the midpoint formula on this?
anonymous
  • anonymous
of course, but the midpoint formula tells you to add up and divide by 2
shamallamadingdong
  • shamallamadingdong
and you would get 2a
anonymous
  • anonymous
yes you would so the first coordinate of the midpoint is \(2a\)
anonymous
  • anonymous
the second coordinate will be \(\frac{a+a}{2}\)
shamallamadingdong
  • shamallamadingdong
witch would be 1a or a
anonymous
  • anonymous
yes so final answer is ?
shamallamadingdong
  • shamallamadingdong
2a,a
anonymous
  • anonymous
right
shamallamadingdong
  • shamallamadingdong
Thanks a ton
anonymous
  • anonymous
and that is all, except i would love to know where this problem came from, there is a big mistake in iti
shamallamadingdong
  • shamallamadingdong
GradPoint
anonymous
  • anonymous
not sure what that is do you see how E is \((a,a)\) and F is \((3a,a)\) in the bottom?
shamallamadingdong
  • shamallamadingdong
ya
anonymous
  • anonymous
that means the second coordinates are the same, they are both \(a\) but in the picture the second coordinates are different since F is LOWER than E
shamallamadingdong
  • shamallamadingdong
and grad point is an online school where you can take full courses or you can use it to get credit recovery
anonymous
  • anonymous
bad picture really bad goes right in the "bad math" pile
anonymous
  • anonymous
yeah on line school, questions always seem to have problems not your fault though, ignore it
shamallamadingdong
  • shamallamadingdong
lol there are lots more questions like this one so might see ya soon :\
anonymous
  • anonymous
kk

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