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anonymous
 one year ago
can somebody please help me with this question? i am completely lost.
Use basic identities to simplify the expression. (picture below)
anonymous
 one year ago
can somebody please help me with this question? i am completely lost. Use basic identities to simplify the expression. (picture below)

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SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0\(\large\color{black}{ \displaystyle \frac{ \cos^2\theta}{\sin^2\theta}+\csc\theta\sin\theta }\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0some basic identities: \(\large \color{black}{\sin\theta\csc\theta=1}\) \(\large \color{black}{\cos\theta\sec\theta=1}\) \(\large \color{black}{\tan\theta\cot\theta=1}\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0i still want to ask, do you have any options?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0these are my options

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0ok, then you need 2 more rules" \(\color{black}{\large \dfrac{\sin\theta}{\cos\theta}=\tan\theta}\) \(\large \color{black}{\tan^2\theta+1=\sec^2\theta}\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0well, the first rule also applies when sine and cosine are raised to any power of n, such that: \(\color{black}{\large \dfrac{\sin^n\theta}{\cos^n\theta}=\tan^n\theta}\) (for all n, of course)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2or maybe u need 2 More rules :3 Mo\[\huge\rm \frac{ \cos \theta }{ \sin \theta}= \cot \theta \] \[\huge\rm cot^2 \theta +1=\csc^2\theta \]

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0oh, Nnesha, you are right, because it is cosine/sine, not the other way around as I thought for some reason:) and thus, the 2nd rule you posted comes about.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so, what exactly do i do with the rules you guys gave me?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0\(\LARGE \color{blue}{\unicode{x10009999999}}\)\(\LARGE \color{blue}{\unicode{x120D999}}\)\(\LARGE \color{blue}{\unicode{x3D5}}\)\(\LARGE \color{blue}{\unicode{x8594}}\) \(\LARGE \color{blue}{:)}\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0u apply them to your problem

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0\(\large\color{black}{ \displaystyle \frac{ \cos^2\theta}{\sin^2\theta}+\csc\theta\sin\theta }\) apply to the second term, one of the rules that I posted in the very beginning.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay what i think i understand is cos^2(theta) / sin^2(theta) = 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would it then be cot^2(theta) = 1 ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2cos^2/sin^2 is not equal to one if cos /sin =cot then cos^2 / sin^2 = cot^2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes right cot^2 theta +1 which is e qual to what ?
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