Determine the factors of 15x2 + 3xy + 10x + 2y.
(3x + 2)(5x + y)
(5x + y)(2x + 3)
(3x + y)(5x + 2)
(5x + 3)(2x + y)

- lalaland_lauren

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- lalaland_lauren

@satellite73

- lalaland_lauren

@vmac2122

- misty1212

HI!!

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## More answers

- lalaland_lauren

Hello :)

- misty1212

we can multiply each one out and see what works, or perhaps we can work smarter

- misty1212

you see how the last term is \(2y\) right?

- lalaland_lauren

That's my problem, I get so confused multiplying everything out :( and yeah

- misty1212

that gets rid if b and d
do you see why?

- lalaland_lauren

Yeah, that's actually a really cool loophole

- misty1212

\[ (5x + y)(2x + 3)\] last term will be \(3y\) so that is no good

- misty1212

same here \[ (5x + 3)(2x + y)\]

- lalaland_lauren

I figured it out, it's A

- misty1212

so we can try the first one \[ (3x + 2)(5x + y)\]

- misty1212

yeah that looks good

- lalaland_lauren

Yayyyyy I got it! :)

- misty1212

\[\huge \color\magenta\heartsuit\]

- lalaland_lauren

Thank youuuu!

- misty1212

you are quite welcome
got more?

- lalaland_lauren

A few, yes hold on

- misty1212

kk

- lalaland_lauren

Graph of a cubic polynomial that falls to the left and rises to the right with graph touching x axis at negative 1 and x intercept at 1
Which of the following functions best represents the graph?
f(x) = x3 + x2 − 4x − 4
f(x) = x3 + x2 − x − 1
f(x) = x3 + 3x2 − 4x − 12
f(x) = x3 + 2x2 − 2x − 1

- lalaland_lauren

##### 1 Attachment

- misty1212

ok we can do this

- misty1212

you see how it only touches where \(x=-1\)?

- lalaland_lauren

Yeah, and where x=1

- misty1212

actually there is a difference,
where \(x=1\) it CROSSES the axis, at \(x=-1\) it comes up, touches it, but does not cross, goes back down

- misty1212

so it has to zeros, one at \(x=-1\) and one at \(x=1\)
because it crosses at \(x=1\) one factor is \((x-1)\)

- misty1212

because it touches at \(x=-1\) then the factor looks like \((x+1)^2\)

- misty1212

lol "has two zeros" i meant

- misty1212

final job is to multiply
\[(x+1)^2(x-1)\] to see what we get
i would cheat!!

- misty1212

http://www.wolframalpha.com/input/?i=%28x%2B1%29%5E2%28x-1%29

- misty1212

looks like \[x^3+x^2-x-1\] is a winner
is that a choice?

- lalaland_lauren

Yup :) Wolfram Alpha has been helping me a lot this unit lol

- misty1212

might as well use it instead of making an algebra mistake
i do!

- lalaland_lauren

Haha! I have just one more question and them I'm done lol

- lalaland_lauren

Which shows 602 − 402 being evaluated using the difference of squares method?
602 − 402 = (3600 + 1600)(3600 − 1600) = 10,400,000
602 − 402 = 3600 − 1600 = 2,000
602 − 402 = (60 − 40)2 = 202 = 400
602 − 402 = (60 + 40)(60 − 40) = (100)(20) = 2,000

- lalaland_lauren

The twos are squares

- misty1212

\[60^2-40^2\]?

- lalaland_lauren

Wait nvm I found the answer haha

- misty1212

D right?

- lalaland_lauren

Yup xD

- lalaland_lauren

I got an 88% :D

- misty1212

that it?

- misty1212

then time for a tune
https://www.youtube.com/watch?v=smdNetoPFV0

- lalaland_lauren

I LOVE THAT SONG!!!!!

- lalaland_lauren

I love that whole band, actually!

- misty1212

lol thought so !!

- lalaland_lauren

How'd you know? XD

- misty1212

american psychic

- lalaland_lauren

*clapping emoji*

- misty1212

\[\color\red\heartsuit\]

- lalaland_lauren

Unfortunately I have to go to bed now :( I'm extremely tired and I'm pretty sure I have to get up early to keep working on assignments. Will you be on in the morning?

- misty1212

i can be here at about 9 or 9:30
earlier probably not

- misty1212

tag me if you like, i will try to help if i can!

- misty1212

my bed time too

- lalaland_lauren

That's a good time for me :) alrighty, thanks so much for helping me! good night c:

- misty1212

gnight c:

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