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anonymous
 one year ago
How would I solve this?
anonymous
 one year ago
How would I solve this?

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SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\large\color{slate}{\displaystyle\lim_{x \rightarrow ~7^}~\dfrac{1}{x7}}\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1well, you know (I would assume) that when you are dealing with a function f(x)=1/(xa) then, your asymptote is x=a

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1So, this way you should be able to identify the asymptote.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Now, you are asked to use a numerical approach (and make a table of values) for this limit. I will show you what to do, and you will complete the chart: keep in mind, your function is \(f(x)=\dfrac{1}{x7}\) and in your limit, the x is appraching 7 from the left side, so we start from values that are smaller than 7 just a bit, and then approach 7 closer and closer "from the left". \(\large\color{black}{ \huge{ \begin{array}{ l  c  r } \hline \scr~~~x~~ & \scr~~~ f(x) ~~~\\ \hline \scr~~~6~ & \scr ~ \\ \hline \scr~~~6.5~ & \scr ~ \\ \hline \scr~~~6.9~ & \scr ~ \\ \hline \scr~~~6.99~ & \scr ~ \\ \hline \scr~~~6.999~ & \scr ~ \\ \hline \end{array} } }\) and using this table you should be able to find the limit: \(\large\color{slate}{\displaystyle\lim_{x \rightarrow ~7~^}~\dfrac{1}{x7}}\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1u can use wolframalpha.com to calculate these values for the table. and these values don't need to be exactly those, just some values that closer and closer approach 7 "from the left".

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01 2 10 100 1000

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1yes.... see where the limit is going as x approaches 7 closer and closer?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1yes, this limit is going towards ∞

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Unless you're willing to help me with another problem, no.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Oh, ok. But in different post if you will. (i will see if I can make it there)
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