anonymous
  • anonymous
What is the phase shift for the equation: y=-3sec(π-2x)+5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@pooja195 @Hero @e.mccormick @SolomonZelman
LynFran
  • LynFran
this equation can be written as y=5-3sec(-2x+pi) where the phase shift would be -2x+pi=0
LynFran
  • LynFran
solve for x ...and thats ur phase shift

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LynFran
  • LynFran
what do u get?
anonymous
  • anonymous
2x/pi
LynFran
  • LynFran
no -2x+pi=0 -2x=-pi divide by -2 x=pi/2
anonymous
  • anonymous
so the phase shift is pi/2
LynFran
  • LynFran
yep
anonymous
  • anonymous
wait I have one more question, is there a such thing of having a phase shift of 0 or is that considered not a phase shift @LynFran
LynFran
  • LynFran
not a phase shift .....a phase shift mean that there a vertical shift ...either to the right or left of the graph
anonymous
  • anonymous
\[y=-2\sin(5/4x) \]
LynFran
  • LynFran
and that new phase shift determines where the graph starts
anonymous
  • anonymous
^Does that equation have no phase shift then^
LynFran
  • LynFran
yes that equation has no phase shift
LynFran
  • LynFran
it just have the amplitude which is |-2|=2 and its period which is 2pi divided by 5/4x
anonymous
  • anonymous
thank you so much
anonymous
  • anonymous
wait I thought the amplitude would just be -2
anonymous
  • anonymous
the amplitude does not have absolute value
anonymous
  • anonymous
F(t) = Af(Bt – C) + D, A is the ampitude
LynFran
  • LynFran
no amplitudes are always the absolute value of the # infront the function /curve .... which means its always positive...
anonymous
  • anonymous
i think that you are wrong
anonymous
  • anonymous
@ganeshie8
LynFran
  • LynFran
check this out http://www.montereyinstitute.org/courses/DevelopmentalMath/COURSE_TEXT2_RESOURCE/U19_L2_T3_text_final.html
anonymous
  • anonymous
OH WAIT YOU ARE RIGHT, I WAS THINKING ABOUT PERIODICITY
anonymous
  • anonymous
IM SO SORRY
anonymous
  • anonymous
@LynFran
LynFran
  • LynFran
its ok

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