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anonymous
 one year ago
What is the phase shift for the equation: y=3sec(π2x)+5
anonymous
 one year ago
What is the phase shift for the equation: y=3sec(π2x)+5

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@pooja195 @Hero @e.mccormick @SolomonZelman

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2this equation can be written as y=53sec(2x+pi) where the phase shift would be 2x+pi=0

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2solve for x ...and thats ur phase shift

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2no 2x+pi=0 2x=pi divide by 2 x=pi/2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the phase shift is pi/2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait I have one more question, is there a such thing of having a phase shift of 0 or is that considered not a phase shift @LynFran

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2not a phase shift .....a phase shift mean that there a vertical shift ...either to the right or left of the graph

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2and that new phase shift determines where the graph starts

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0^Does that equation have no phase shift then^

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2yes that equation has no phase shift

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2it just have the amplitude which is 2=2 and its period which is 2pi divided by 5/4x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait I thought the amplitude would just be 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the amplitude does not have absolute value

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0F(t) = Af(Bt – C) + D, A is the ampitude

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2no amplitudes are always the absolute value of the # infront the function /curve .... which means its always positive...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think that you are wrong

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2check this out http://www.montereyinstitute.org/courses/DevelopmentalMath/COURSE_TEXT2_RESOURCE/U19_L2_T3_text_final.html

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OH WAIT YOU ARE RIGHT, I WAS THINKING ABOUT PERIODICITY
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