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anonymous

  • one year ago

What is the phase shift for the equation: y=-3sec(π-2x)+5

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  1. anonymous
    • one year ago
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    @pooja195 @Hero @e.mccormick @SolomonZelman

  2. LynFran
    • one year ago
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    this equation can be written as y=5-3sec(-2x+pi) where the phase shift would be -2x+pi=0

  3. LynFran
    • one year ago
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    solve for x ...and thats ur phase shift

  4. LynFran
    • one year ago
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    what do u get?

  5. anonymous
    • one year ago
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    2x/pi

  6. LynFran
    • one year ago
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    no -2x+pi=0 -2x=-pi divide by -2 x=pi/2

  7. anonymous
    • one year ago
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    so the phase shift is pi/2

  8. LynFran
    • one year ago
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    yep

  9. anonymous
    • one year ago
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    wait I have one more question, is there a such thing of having a phase shift of 0 or is that considered not a phase shift @LynFran

  10. LynFran
    • one year ago
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    not a phase shift .....a phase shift mean that there a vertical shift ...either to the right or left of the graph

  11. anonymous
    • one year ago
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    \[y=-2\sin(5/4x) \]

  12. LynFran
    • one year ago
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    and that new phase shift determines where the graph starts

  13. anonymous
    • one year ago
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    ^Does that equation have no phase shift then^

  14. LynFran
    • one year ago
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    yes that equation has no phase shift

  15. LynFran
    • one year ago
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    it just have the amplitude which is |-2|=2 and its period which is 2pi divided by 5/4x

  16. anonymous
    • one year ago
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    thank you so much

  17. anonymous
    • one year ago
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    wait I thought the amplitude would just be -2

  18. anonymous
    • one year ago
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    the amplitude does not have absolute value

  19. anonymous
    • one year ago
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    F(t) = Af(Bt – C) + D, A is the ampitude

  20. LynFran
    • one year ago
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    no amplitudes are always the absolute value of the # infront the function /curve .... which means its always positive...

  21. anonymous
    • one year ago
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    i think that you are wrong

  22. anonymous
    • one year ago
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    @ganeshie8

  23. LynFran
    • one year ago
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    check this out http://www.montereyinstitute.org/courses/DevelopmentalMath/COURSE_TEXT2_RESOURCE/U19_L2_T3_text_final.html

  24. anonymous
    • one year ago
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    OH WAIT YOU ARE RIGHT, I WAS THINKING ABOUT PERIODICITY

  25. anonymous
    • one year ago
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    IM SO SORRY

  26. anonymous
    • one year ago
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    @LynFran

  27. LynFran
    • one year ago
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    its ok

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