## anonymous one year ago What is the phase shift for the equation: y=-3sec(π-2x)+5

1. anonymous

@pooja195 @Hero @e.mccormick @SolomonZelman

2. LynFran

this equation can be written as y=5-3sec(-2x+pi) where the phase shift would be -2x+pi=0

3. LynFran

solve for x ...and thats ur phase shift

4. LynFran

what do u get?

5. anonymous

2x/pi

6. LynFran

no -2x+pi=0 -2x=-pi divide by -2 x=pi/2

7. anonymous

so the phase shift is pi/2

8. LynFran

yep

9. anonymous

wait I have one more question, is there a such thing of having a phase shift of 0 or is that considered not a phase shift @LynFran

10. LynFran

not a phase shift .....a phase shift mean that there a vertical shift ...either to the right or left of the graph

11. anonymous

$y=-2\sin(5/4x)$

12. LynFran

and that new phase shift determines where the graph starts

13. anonymous

^Does that equation have no phase shift then^

14. LynFran

yes that equation has no phase shift

15. LynFran

it just have the amplitude which is |-2|=2 and its period which is 2pi divided by 5/4x

16. anonymous

thank you so much

17. anonymous

wait I thought the amplitude would just be -2

18. anonymous

the amplitude does not have absolute value

19. anonymous

F(t) = Af(Bt – C) + D, A is the ampitude

20. LynFran

no amplitudes are always the absolute value of the # infront the function /curve .... which means its always positive...

21. anonymous

i think that you are wrong

22. anonymous

@ganeshie8

23. LynFran
24. anonymous

OH WAIT YOU ARE RIGHT, I WAS THINKING ABOUT PERIODICITY

25. anonymous

IM SO SORRY

26. anonymous

@LynFran

27. LynFran

its ok