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anonymous

  • one year ago

help plz Write an equation of a line perpendicular to y = 1/2x - 5 in slope-intercept form that passes through the point (2, -7). y=1/2 x - 7 y= 2x + 2 y= -2x - 5 y= -2x - 3

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  1. Zale101
    • one year ago
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    So, you are given an equation to determine a perpendicular line with a given point. From the given equation y = 1/2x - 5 you identify the slope. Convert the original slope into a perpendicular line slope, and by that, you take the negative reciprocal of it. \(\Large m=-\frac{1}{m}\) Place the new perpendicular slope and the given point (2,-7)=(x1,y1) into the point slope formula \(y-y_1=-\frac{1}{m}(x-x_1)\)

  2. anonymous
    • one year ago
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    so y- (-7) = -1/m(x-2) where do i go from here @Zale101

  3. anonymous
    • one year ago
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    @Hero could you please help me finish this

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