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anonymous

  • one year ago

help please, check the attachment, thank you!!

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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  3. UsukiDoll
    • one year ago
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    given yogurt sundae represented by x and costs $4 yogurt cone represented by y and costs $3 we got a $50 card it's like the equation is 4x+3y=50 so that could be 4x+3y < 50 4x+3y > 50 \[4x+3y \leq 50\] or \[4x+3y \geq 50 \]

  4. anonymous
    • one year ago
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    do you know which one of the graphs it would be? @UsukiDoll I'm stuck between A and C

  5. UsukiDoll
    • one year ago
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    I haven't done this in years, so I'm thinking xD

  6. anonymous
    • one year ago
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    @UsukiDoll lol thanks for trying

  7. UsukiDoll
    • one year ago
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    you have to graph the line of 4x+3y = 50 first

  8. UsukiDoll
    • one year ago
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    change it to the y =mx+b form

  9. jim_thompson5910
    • one year ago
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    Let T be the total cost of buying x sundaes and y cones Since you only have $50, this means that is the most you can spend. It is the ceiling. So that's why \[\Large T \le 50\] T could be less than 50 or it could be equal to 50. 1 sundae costs $4, so x of them cost 4x dollars 1 cone costs $3, so y of them cost 3y dollars buying x sundaes and y cones gives a total of 4x+3y dollars, so T = 4x+3y Plug that into the inequality \[\Large T \le 50\] \[\Large 4x+3y \le 50\]

  10. UsukiDoll
    • one year ago
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    ah .. I might have overlooked that $50 limit... so we have to be less than $50 or equal to $50 for this... And since we have \[\LARGE \leq \], it's a solid line

  11. UsukiDoll
    • one year ago
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    so the dash choices are out. now let's pick a test point like the origin (0,0) also known as x = 0 and y =0 and plug it into the equation to see if the inequality is true or false \[\Large 4x+3y \le 50 \] letting x = 0 and y = 0 \[\Large 4(0)+3(0) \le 50 \] \[\Large 0+0 \le 50 \] \[\Large 0 \le 50 \] since 0 is less than or equal to 50. we have to shade the line that includes (0,0)

  12. UsukiDoll
    • one year ago
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    your graph should look like this

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