help please, check the attachment, thank you!!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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- anonymous

help please, check the attachment, thank you!!

- jamiebookeater

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- anonymous

##### 1 Attachment

- anonymous

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- UsukiDoll

given
yogurt sundae represented by x and costs $4
yogurt cone represented by y and costs $3
we got a $50 card
it's like the equation is 4x+3y=50
so that could be
4x+3y < 50
4x+3y > 50
\[4x+3y \leq 50\]
or
\[4x+3y \geq 50 \]

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- anonymous

do you know which one of the graphs it would be? @UsukiDoll I'm stuck between A and C

- UsukiDoll

I haven't done this in years, so I'm thinking xD

- anonymous

@UsukiDoll lol thanks for trying

- UsukiDoll

you have to graph the line of 4x+3y = 50 first

- UsukiDoll

change it to the y =mx+b form

- jim_thompson5910

Let T be the total cost of buying x sundaes and y cones
Since you only have $50, this means that is the most you can spend. It is the ceiling. So that's why \[\Large T \le 50\] T could be less than 50 or it could be equal to 50.
1 sundae costs $4, so x of them cost 4x dollars
1 cone costs $3, so y of them cost 3y dollars
buying x sundaes and y cones gives a total of 4x+3y dollars, so T = 4x+3y
Plug that into the inequality
\[\Large T \le 50\]
\[\Large 4x+3y \le 50\]

- UsukiDoll

ah .. I might have overlooked that $50 limit... so we have to be less than $50 or equal to $50 for this... And since we have \[\LARGE \leq \], it's a solid line

- UsukiDoll

so the dash choices are out.
now let's pick a test point like the origin (0,0) also known as x = 0 and y =0 and plug it into the equation to see if the inequality is true or false
\[\Large 4x+3y \le 50 \]
letting x = 0 and y = 0
\[\Large 4(0)+3(0) \le 50 \]
\[\Large 0+0 \le 50 \]
\[\Large 0 \le 50 \]
since 0 is less than or equal to 50. we have to shade the line that includes (0,0)

- UsukiDoll

your graph should look like this

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