## anonymous one year ago help please, check the attachment, thank you!!

1. anonymous

2. anonymous

3. UsukiDoll

given yogurt sundae represented by x and costs $4 yogurt cone represented by y and costs$3 we got a $50 card it's like the equation is 4x+3y=50 so that could be 4x+3y < 50 4x+3y > 50 $4x+3y \leq 50$ or $4x+3y \geq 50$ 4. anonymous do you know which one of the graphs it would be? @UsukiDoll I'm stuck between A and C 5. UsukiDoll I haven't done this in years, so I'm thinking xD 6. anonymous @UsukiDoll lol thanks for trying 7. UsukiDoll you have to graph the line of 4x+3y = 50 first 8. UsukiDoll change it to the y =mx+b form 9. jim_thompson5910 Let T be the total cost of buying x sundaes and y cones Since you only have$50, this means that is the most you can spend. It is the ceiling. So that's why $\Large T \le 50$ T could be less than 50 or it could be equal to 50. 1 sundae costs $4, so x of them cost 4x dollars 1 cone costs$3, so y of them cost 3y dollars buying x sundaes and y cones gives a total of 4x+3y dollars, so T = 4x+3y Plug that into the inequality $\Large T \le 50$ $\Large 4x+3y \le 50$

10. UsukiDoll

ah .. I might have overlooked that $50 limit... so we have to be less than$50 or equal to \$50 for this... And since we have $\LARGE \leq$, it's a solid line

11. UsukiDoll

so the dash choices are out. now let's pick a test point like the origin (0,0) also known as x = 0 and y =0 and plug it into the equation to see if the inequality is true or false $\Large 4x+3y \le 50$ letting x = 0 and y = 0 $\Large 4(0)+3(0) \le 50$ $\Large 0+0 \le 50$ $\Large 0 \le 50$ since 0 is less than or equal to 50. we have to shade the line that includes (0,0)

12. UsukiDoll

your graph should look like this