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anonymous

  • one year ago

suppose f(x)=x^3+1. find the graph of f(2x)

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  1. anonymous
    • one year ago
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    i don't understand it at all

  2. UsukiDoll
    • one year ago
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    we are given the function \[f(x) =x^3+1 \] that should be graphed first and then we apply the f(2x) in this case x = [2x] into the original function and that modification should be graphed second.

  3. arindameducationusc
    • one year ago
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    I agree with @UsukiDoll

  4. UsukiDoll
    • one year ago
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    :) thank you @arindameducationusc

  5. welshfella
    • one year ago
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    the graph will be a stretch of factor 2 of f(x) parallel to the y-axis.

  6. anonymous
    • one year ago
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  7. welshfella
    • one year ago
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    which one has that stretch?

  8. anonymous
    • one year ago
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    i think the third down

  9. arindameducationusc
    • one year ago
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    This should help for more....

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  10. welshfella
    • one year ago
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    well its not easy to see unless you have the graph of x^3 + 1 also

  11. anonymous
    • one year ago
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    true

  12. welshfella
    • one year ago
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    ff(2x) will bring the graph closer to the y-axis. It will still go through the point (0,1)

  13. welshfella
    • one year ago
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    i think its B

  14. welshfella
    • one year ago
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    - but you really need to draw them to make sure

  15. UsukiDoll
    • one year ago
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    graph f(x) = x^3+1 and then apply the f(2x) your modified function should look like this f(2x)=8x^3+1

  16. welshfella
    • one year ago
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    yes

  17. welshfella
    • one year ago
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    to see the graphs go the desmos calculator web site

  18. welshfella
    • one year ago
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    very roughly the graphs are |dw:1437999923777:dw|

  19. anonymous
    • one year ago
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    thx

  20. welshfella
    • one year ago
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    yw - the 8x^3 + 1 is the 'skinnier' graph its graph B of you choices

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