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anonymous

  • one year ago

In this question... (image coming). What is Water[t] ? Is it the integral of this function, or is it this function?

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  1. anonymous
    • one year ago
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    Im wondering how you approach a problem like this

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  2. anonymous
    • one year ago
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    ok so water[t]= 21000 E^t / 4.1 + 1.2 E^t

  3. phi
    • one year ago
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    it gives the amount of water in the tank as a function of t

  4. phi
    • one year ago
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    it would be the integral of the rate

  5. anonymous
    • one year ago
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    but it seems to cap out at 210000 ? when I do that

  6. anonymous
    • one year ago
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    well not quite... but it stops early

  7. welshfella
    • one year ago
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    my mistake - i misread the question

  8. anonymous
    • one year ago
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    are you sure that equation is not just the fill rate? The rate of change? and I have to integrate it into a volume?

  9. phi
    • one year ago
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    the rate is approaches a limit but \[ W(t)= \int_0^T r(t) \ dt \] where r(t) is your messy expression

  10. phi
    • one year ago
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    ** W(T)=...

  11. anonymous
    • one year ago
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    Im not sure if this makes sense.. but I cooked this up in mathematica.. why does it seem to start out at 210000 cu ft?

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  12. anonymous
    • one year ago
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    should I be using definite integration not indefinite?

  13. anonymous
    • one year ago
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    nm, I think you answered that already in your post phi

  14. phi
    • one year ago
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    there is the initial condition that W(0)= 0 (it is empty at t=0)

  15. anonymous
    • one year ago
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    integrating from 0 to T with W[0] = 0 .. empty tank.. gotcha

  16. phi
    • one year ago
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    and then rename T to t so you have W[t] that you plot as a function of t

  17. anonymous
    • one year ago
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    I think this look right...

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  18. anonymous
    • one year ago
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    Thanks Phi

  19. anonymous
    • one year ago
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    Should be good from here..

  20. phi
    • one year ago
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    yes, looks good

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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