anonymous
  • anonymous
Challenge! Ready? A boat in calm seas travels in a straight line and ends the trip 22 km west and 53 km north of its original position. To the nearest tenth of a degree, find the direction of the trip.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
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anonymous
  • anonymous
You use that right?
anonymous
  • anonymous
So is it just the normal challenge or are you actually solving it this time?

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anonymous
  • anonymous
I wasn't sure about this one.
radar
  • radar
|dw:1438001626918:dw|
anonymous
  • anonymous
Assume the start is at (0,0) The end is at (-22,53). ---- direction = tan^-1(-53/22) = -67.46 But the angle is in the 2nd Quadrant. So, direction = -67.46 + 180 = 112.54 degrees. Is this right?
radar
  • radar
|dw:1438001867988:dw|
anonymous
  • anonymous
So did I do that correctly?
anonymous
  • anonymous
or noo
anonymous
  • anonymous
arctan(53/22)=67.5° N 22.5° W, 22.5° west of north
radar
  • radar
I got an angle of 22.5 degrees West of North, that would resolve to a bearing of 360-22.5 degrees or 337.5 degrees on a compass.
radar
  • radar
Taking in consideration that North is 0 degrees, I say you got it right.
radar
  • radar
Note that direction, North is 0 degrees and then you rotate clockwise, East is 90 degree, South is 180 degress etc.
radar
  • radar
However, I would check with your instructor, what he wants
radar
  • radar
22.5 West of North also describes it well.
anonymous
  • anonymous
And it was right to this? http://assets.openstudy.com/updates/attachments/55b62750e4b0d48ca8eef4f1-lollygirl217-1438001228465-as.jpg
radar
  • radar
That describes the absolute angle. But you are asked for "direction"
radar
  • radar
Your response 22.5 degrees west of north, should be satisfactory.
radar
  • radar
See. https://en.wikipedia.org/wiki/Compass_rose

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