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anonymous

  • one year ago

Given that m<A= (5y+11)° , m<D = (12y-10)° , m<E = 51° , and m<F = (30y + 13). Find m<A.

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  1. anonymous
    • one year ago
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  2. Nnesha
    • one year ago
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    m<C = m<F m<A=m<D m<B=m<E |dw:1438003089618:dw| equal lines shows that m<C = m<F m<A=m<D m<B=m<E

  3. anonymous
    • one year ago
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    ooh, so how do I solve..?

  4. Nnesha
    • one year ago
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    first you need to find y so they gave m<D ,m<E ,m<F all triangles add up to 180 so set it equal to 180 \[\huge\rm 12y-10+51+30y+13 =180\] solve for y

  5. Nnesha
    • one year ago
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    or you can set first triangle equal to 180 doesn't matter you will get the same answer m<A+m<B+m<C =180

  6. anonymous
    • one year ago
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    This is yet another dumb question. but is the 10 a negative and how do I add hat to 1 and 13?

  7. anonymous
    • one year ago
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    I meant 51, not 1 haha

  8. Nnesha
    • one year ago
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    well by adding i mean m<F+m<E+m<D add them together

  9. anonymous
    • one year ago
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    Ugh, this confuses me so much..

  10. Nnesha
    • one year ago
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    and ofc m<D is 12y negative then you have to subtract

  11. Nnesha
    • one year ago
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    m<F = 30y +13 m<d= 12y -10 m<E = 51 so I just replaced m<F,m<D,m<F by their values now solve for y

  12. Nnesha
    • one year ago
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    combine like terms 't left side first you need to find y \[\huge\rm \color{reD}{12y}\color{blue}{-10}\color{blue}{+51}+\color{reD}{30y}+\color{blue}{13 }=180\]

  13. phi
    • one year ago
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    you can think of the 12y -10 as 12y + (-10) you can re-arrange the additions to look like this 12y + 30y + (-10) +51+13 = 180 add up: 12 y's plus 30 more y's is how many y's? and the numbers: 51+13 + -10= ? you should get 42y +54= 180 now add -54 to both sides (write -54 on both sides) and then simplify

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