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anonymous
 one year ago
MEDALLLLL!!!
1There are 100 runners entered in a marathon. How many different groups of three runners can finish in first, second, and third?
Does this problem involve permutations or combinations?
2There are 100 runners entered in a marathon. Trophies are awarded for first place, second place, and third place. In how many different ways could the runners receive trophies?
Does this problem involve permutations or combinations?
anonymous
 one year ago
MEDALLLLL!!! 1There are 100 runners entered in a marathon. How many different groups of three runners can finish in first, second, and third? Does this problem involve permutations or combinations? 2There are 100 runners entered in a marathon. Trophies are awarded for first place, second place, and third place. In how many different ways could the runners receive trophies? Does this problem involve permutations or combinations?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The question states "groups of 3". In other words A first, B second and C third is exactly the same group of three as B first C second and A third. Where order of selection doesn't matter you use combinations. Where order of selection does matter you use permutations. Therefore the answer = 100C3 or choose any three from 100 = 100! / (3!97!) = (100 * 99 * 98 * 97!) / (3 *2 * 1 *97!) = 100* 99 * 98 /6 = 161700

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You would do the second part the same way

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you would do it the same way
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