For minimum or maximum just differentiate it.
you are going to put the thing in a form y = a( x - h)^2 + k by completing the square..
Maximum at (1,1)
for vertex Apply x=-b/2a
do you have to show the completing the square work?
know just min and max and what point
So you dont need the way... okay i will give you max/min
i am pretty sure it is min but i don't know the coordinates
Yes it is minima, it is (-1,-5)..
you have the wrong coordinates