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anonymous
 one year ago
What causes a solution to a rational equation to be an extraneous solution?
When there is more than one solution, one of the solutions is extraneous.
If a solution results in zero when substituted into the denominator of the equation, the solution is extraneous.
If a solution results in a negative number when substituted into the denominator of the equation, the solution is extraneous.
When a solution is a fraction, the solution is extraneous.
anonymous
 one year ago
What causes a solution to a rational equation to be an extraneous solution? When there is more than one solution, one of the solutions is extraneous. If a solution results in zero when substituted into the denominator of the equation, the solution is extraneous. If a solution results in a negative number when substituted into the denominator of the equation, the solution is extraneous. When a solution is a fraction, the solution is extraneous.

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DanJS
 one year ago
Best ResponseYou've already chosen the best response.0dividing by zero breaks maths

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0here are a couple short vids that probably are decent, they usually cover the basics... https://www.khanacademy.org/math/algebra2/rationalexpressions/solvingrationalequations/v/extraneoussolutionstorationalequations

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i tried that i still didnt understand

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0If you have an equation like \[\frac{ x^2 }{ (x+2 )} = \frac{ 4 }{ (x+2) }\]

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0if x = 2, the denominators become zero, and that is not allowed. So X can not be 2... now try to solve it...

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0multiply both sides by x+2 gives \[x^2 = 4\] \[x = \sqrt{4} = \pm2\]

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0The solutions from solving say that X can be +2 or 2. however, When X=2, the original equation is undefined (zero in denominator) so x=2 is an "extraneous": solution.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so youre saying If a solution results in a negative number when substituted into the denominator of the equation, the solution is extraneous

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0no, the denominator can not be zero. If one of the solutions for X causes the denominator of the original equation to be zero, then it is extraneous solution

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0For the above example, the x=2, causes (x+2) to be zero

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0we can do another example if you want, there is one from that same site i linked
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