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anonymous

  • one year ago

The volume of a cone is 183.26 cubic feet and its radius is 5 feet. What is the cone's height? Round to the nearest foot. Use 3.14 for \pi .

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  1. anonymous
    • one year ago
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    @DaBest21

  2. Michele_Laino
    • one year ago
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    here we have to use this formula: \[\Large V = \frac{{\pi {r^2}h}}{3}\]

  3. Michele_Laino
    • one year ago
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    where V is the volume of the cone, r is the radius of its base, and h is the height of the cone

  4. anonymous
    • one year ago
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    \[3\frac{ 183.26}{ 3.14*5*5 }\]is the formula @Aliypop

  5. anonymous
    • one year ago
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    so do 3.14*5*5 first @Aliypop

  6. Michele_Laino
    • one year ago
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    from that formula above we get: \[h = \frac{{3V}}{{\pi {r^2}}} = \frac{{3 \times 183.26}}{{3.14 \times 5 \times 5}} = ...feet\]

  7. anonymous
    • one year ago
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    78.5

  8. anonymous
    • one year ago
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    yep now do 183.26/78.5

  9. anonymous
    • one year ago
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    2.33452293

  10. Michele_Laino
    • one year ago
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    hint: \[h = \frac{{3V}}{{\pi {r^2}}} = \frac{{3 \times 183.26}}{{3.14 \times 5 \times 5}} = 3 \times 2.335 = ...feet\]

  11. anonymous
    • one year ago
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    2.3335

  12. anonymous
    • one year ago
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    what's the next step ?

  13. Michele_Laino
    • one year ago
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    as I wrote before, what is: 3*2.335=...?

  14. anonymous
    • one year ago
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    7.005

  15. Michele_Laino
    • one year ago
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    that's right!

  16. anonymous
    • one year ago
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    so7.005 is the answer?

  17. Michele_Laino
    • one year ago
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    yes!

  18. anonymous
    • one year ago
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    no

  19. anonymous
    • one year ago
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    u have to round

  20. anonymous
    • one year ago
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    okay :D

  21. anonymous
    • one year ago
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    @Aliypop round

  22. Michele_Laino
    • one year ago
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    yes! sorry @Aliypop you have to round off to the hearest unit of foot

  23. Michele_Laino
    • one year ago
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    nearest*

  24. anonymous
    • one year ago
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    so what does 0 tell u to do to 7 Hint less than 5 means stay the same

  25. anonymous
    • one year ago
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    so would it be 8.00

  26. anonymous
    • one year ago
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    no it would be 7 Don't forget to medal and fan if you already haven't. Plus send me a message if you need more help @Aliypop

  27. anonymous
    • one year ago
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    Carson's Bakery and Chocolate Shop is experimenting with making chocolate in the shape of different types of sports equipment. Bayside High School's Volleyball team has ordered 100 solid white chocolate volleyballs. What volume of white chocolate is needed to fill this order if the radius of each volleyball is 4 cm? Rounded to the nearest tenth of a cubic centimeter. Use 3.14 for \pi .

  28. anonymous
    • one year ago
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    it appeared wrong again

  29. anonymous
    • one year ago
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    we did this already didnt we? @Aliypop

  30. anonymous
    • one year ago
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    @welshfella

  31. anonymous
    • one year ago
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    @welshfella @welshfella

  32. anonymous
    • one year ago
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    I got 211 now as the answer

  33. Michele_Laino
    • one year ago
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    hint: the volume V of a sphere is given by the subsequent equation (pi=3.14): \[\begin{gathered} V = \frac{{4 \times 3.14}}{3}{r^3} = \frac{{12.56}}{3} \times {r^3} = \hfill \\ \hfill \\ = \frac{{12.56}}{3} \times {4^3} = \frac{{12.56}}{3} \times 64 = ...? \hfill \\ \end{gathered} \]

  34. anonymous
    • one year ago
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    2,411.25

  35. Michele_Laino
    • one year ago
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    I got this: \[\begin{gathered} V = \frac{{4 \times 3.14}}{3}{r^3} = \frac{{12.56}}{3} \times {r^3} = \hfill \\ \hfill \\ = \frac{{12.56}}{3} \times {4^3} = \frac{{12.56}}{3} \times 64 = 267.85c{m^3} \hfill \\ \end{gathered} \]

  36. anonymous
    • one year ago
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    okay

  37. anonymous
    • one year ago
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    so 267.9

  38. Michele_Laino
    • one year ago
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    sorry I have made an error, here is the right result: \[\begin{gathered} V = \frac{{4 \times 3.14}}{3}{r^3} = \frac{{12.56}}{3} \times {r^3} = \hfill \\ \hfill \\ = \frac{{12.56}}{3} \times {4^3} = \frac{{12.56}}{3} \times 64 = 267.9466c{m^3} \hfill \\ \end{gathered} \] so the total volume of the requested chocolate is: \[V = 100 \times 267.9466 = 26794.66 \cong 26794.7c{m^3}\]

  39. anonymous
    • one year ago
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    okay

  40. anonymous
    • one year ago
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    so rounded to the nearest foot it is 267.9

  41. Michele_Laino
    • one year ago
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    267.9 is the volume of a single volleyball

  42. Michele_Laino
    • one year ago
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    the requested volume of needed white chocolate is: \[V \cong 26794.7c{m^3}\]

  43. anonymous
    • one year ago
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    The new business building uptown is building a wall made entirely of glass pyramids. Each pyramid will have a square base with length of 8 inches and height of 10 inches. If the wall requires 250 of these pyramids, what volume of glass will be used? Round to the nearest cubic inch.

  44. Michele_Laino
    • one year ago
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    we have to compute the volume V of a single pyramid. So, we can apply this formula: \[\Large V = \frac{1}{3}L \times L \times H\] where L is the length of the square base, and H is the height of the pyramid: |dw:1438014203141:dw|

  45. anonymous
    • one year ago
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    okay

  46. Michele_Laino
    • one year ago
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    substituting your data, we have: \[\begin{gathered} V = \frac{1}{3}L \times L \times H = \hfill \\ \hfill \\ = \frac{1}{3}8 \times 8 \times 10 = \frac{{640}}{3} = ...inche{s^3} \hfill \\ \end{gathered} \]

  47. anonymous
    • one year ago
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    213.333333

  48. Michele_Laino
    • one year ago
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    correct!

  49. Michele_Laino
    • one year ago
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    Now, we have 250 of such pyramids, so the requested volume of needed glass, is: \[{V_{TOTAL}} = 213.3333 \times 250 = \]

  50. anonymous
    • one year ago
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    53,33.333333

  51. Michele_Laino
    • one year ago
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    that's right! Now we have to round off that result to the nearest unit, so we get: \[{V_{TOTAL}} = 213.3333 \times 250 = {\text{53333}}{\text{.325}} \cong {\text{53333}}inche{s^3}\]

  52. anonymous
    • one year ago
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    ok

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