anonymous
  • anonymous
The volume of a cone is 183.26 cubic feet and its radius is 5 feet. What is the cone's height? Round to the nearest foot. Use 3.14 for \pi .
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@DaBest21
Michele_Laino
  • Michele_Laino
here we have to use this formula: \[\Large V = \frac{{\pi {r^2}h}}{3}\]
Michele_Laino
  • Michele_Laino
where V is the volume of the cone, r is the radius of its base, and h is the height of the cone

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
\[3\frac{ 183.26}{ 3.14*5*5 }\]is the formula @Aliypop
anonymous
  • anonymous
so do 3.14*5*5 first @Aliypop
Michele_Laino
  • Michele_Laino
from that formula above we get: \[h = \frac{{3V}}{{\pi {r^2}}} = \frac{{3 \times 183.26}}{{3.14 \times 5 \times 5}} = ...feet\]
anonymous
  • anonymous
78.5
anonymous
  • anonymous
yep now do 183.26/78.5
anonymous
  • anonymous
2.33452293
Michele_Laino
  • Michele_Laino
hint: \[h = \frac{{3V}}{{\pi {r^2}}} = \frac{{3 \times 183.26}}{{3.14 \times 5 \times 5}} = 3 \times 2.335 = ...feet\]
anonymous
  • anonymous
2.3335
anonymous
  • anonymous
what's the next step ?
Michele_Laino
  • Michele_Laino
as I wrote before, what is: 3*2.335=...?
anonymous
  • anonymous
7.005
Michele_Laino
  • Michele_Laino
that's right!
anonymous
  • anonymous
so7.005 is the answer?
Michele_Laino
  • Michele_Laino
yes!
anonymous
  • anonymous
no
anonymous
  • anonymous
u have to round
anonymous
  • anonymous
okay :D
anonymous
  • anonymous
@Aliypop round
Michele_Laino
  • Michele_Laino
yes! sorry @Aliypop you have to round off to the hearest unit of foot
Michele_Laino
  • Michele_Laino
nearest*
anonymous
  • anonymous
so what does 0 tell u to do to 7 Hint less than 5 means stay the same
anonymous
  • anonymous
so would it be 8.00
anonymous
  • anonymous
no it would be 7 Don't forget to medal and fan if you already haven't. Plus send me a message if you need more help @Aliypop
anonymous
  • anonymous
Carson's Bakery and Chocolate Shop is experimenting with making chocolate in the shape of different types of sports equipment. Bayside High School's Volleyball team has ordered 100 solid white chocolate volleyballs. What volume of white chocolate is needed to fill this order if the radius of each volleyball is 4 cm? Rounded to the nearest tenth of a cubic centimeter. Use 3.14 for \pi .
anonymous
  • anonymous
it appeared wrong again
anonymous
  • anonymous
we did this already didnt we? @Aliypop
anonymous
  • anonymous
@welshfella
anonymous
  • anonymous
@welshfella @welshfella
anonymous
  • anonymous
I got 211 now as the answer
Michele_Laino
  • Michele_Laino
hint: the volume V of a sphere is given by the subsequent equation (pi=3.14): \[\begin{gathered} V = \frac{{4 \times 3.14}}{3}{r^3} = \frac{{12.56}}{3} \times {r^3} = \hfill \\ \hfill \\ = \frac{{12.56}}{3} \times {4^3} = \frac{{12.56}}{3} \times 64 = ...? \hfill \\ \end{gathered} \]
anonymous
  • anonymous
2,411.25
Michele_Laino
  • Michele_Laino
I got this: \[\begin{gathered} V = \frac{{4 \times 3.14}}{3}{r^3} = \frac{{12.56}}{3} \times {r^3} = \hfill \\ \hfill \\ = \frac{{12.56}}{3} \times {4^3} = \frac{{12.56}}{3} \times 64 = 267.85c{m^3} \hfill \\ \end{gathered} \]
anonymous
  • anonymous
okay
anonymous
  • anonymous
so 267.9
Michele_Laino
  • Michele_Laino
sorry I have made an error, here is the right result: \[\begin{gathered} V = \frac{{4 \times 3.14}}{3}{r^3} = \frac{{12.56}}{3} \times {r^3} = \hfill \\ \hfill \\ = \frac{{12.56}}{3} \times {4^3} = \frac{{12.56}}{3} \times 64 = 267.9466c{m^3} \hfill \\ \end{gathered} \] so the total volume of the requested chocolate is: \[V = 100 \times 267.9466 = 26794.66 \cong 26794.7c{m^3}\]
anonymous
  • anonymous
okay
anonymous
  • anonymous
so rounded to the nearest foot it is 267.9
Michele_Laino
  • Michele_Laino
267.9 is the volume of a single volleyball
Michele_Laino
  • Michele_Laino
the requested volume of needed white chocolate is: \[V \cong 26794.7c{m^3}\]
anonymous
  • anonymous
The new business building uptown is building a wall made entirely of glass pyramids. Each pyramid will have a square base with length of 8 inches and height of 10 inches. If the wall requires 250 of these pyramids, what volume of glass will be used? Round to the nearest cubic inch.
Michele_Laino
  • Michele_Laino
we have to compute the volume V of a single pyramid. So, we can apply this formula: \[\Large V = \frac{1}{3}L \times L \times H\] where L is the length of the square base, and H is the height of the pyramid: |dw:1438014203141:dw|
anonymous
  • anonymous
okay
Michele_Laino
  • Michele_Laino
substituting your data, we have: \[\begin{gathered} V = \frac{1}{3}L \times L \times H = \hfill \\ \hfill \\ = \frac{1}{3}8 \times 8 \times 10 = \frac{{640}}{3} = ...inche{s^3} \hfill \\ \end{gathered} \]
anonymous
  • anonymous
213.333333
Michele_Laino
  • Michele_Laino
correct!
Michele_Laino
  • Michele_Laino
Now, we have 250 of such pyramids, so the requested volume of needed glass, is: \[{V_{TOTAL}} = 213.3333 \times 250 = \]
anonymous
  • anonymous
53,33.333333
Michele_Laino
  • Michele_Laino
that's right! Now we have to round off that result to the nearest unit, so we get: \[{V_{TOTAL}} = 213.3333 \times 250 = {\text{53333}}{\text{.325}} \cong {\text{53333}}inche{s^3}\]
anonymous
  • anonymous
ok

Looking for something else?

Not the answer you are looking for? Search for more explanations.