anonymous
  • anonymous
Given the following functions f(x) and g(x), solve f[g(6)] and select the correct answer below: f(x) = 6x + 12 g(x) = x − 8
Mathematics
schrodinger
  • schrodinger
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triciaal
  • triciaal
work from the inside find g(6) then use this value as the x in f(x)
anonymous
  • anonymous
can u give me the first step please cuz am in a hurry and i need help with another question similar to this one
triciaal
  • triciaal
|dw:1438011683998:dw|

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triciaal
  • triciaal
|dw:1438011729125:dw|
triciaal
  • triciaal
what is the value for g(6) ?
anonymous
  • anonymous
triciaal
  • triciaal
why are you being rude and ungrateful ? when you tag someone else while you are being helped and do not want to participate will not let you learn apparently you do not even want to answer what is 6 minus 8 . I have done the problem it would be to your advantage to read the responses and try rather than expect answers.
anonymous
  • anonymous
i dont know any of this
anonymous
  • anonymous
and am not being rude
Nnesha
  • Nnesha
hey same like last one so first you need to find g(6) as triciaal mentioned
anonymous
  • anonymous
i dont get it
Nnesha
  • Nnesha
first deal with red part \[f[\color{Red}{g(6)}]\] g(6) means x =6 so substitute x for 6 in g(x) function
anonymous
  • anonymous
-2
Nnesha
  • Nnesha
yes right so g(6) = -2 so substitute x for -2 in f(x) function that's what they are asking f(g(6) =
anonymous
  • anonymous
so the eguation would be f(x)=6(-2)+12
Nnesha
  • Nnesha
yep right
anonymous
  • anonymous
f(x)=0
Nnesha
  • Nnesha
not f(x) f(g(6)) = 0
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @maria12vera so the eguation would be f(x)=6(-2)+12 \(\color{blue}{\text{End of Quote}}\) it's f(g(6)) which is f(-2) you don't have to solve left side but better to show that what we are solving for so it's f(g(6)) = 0 :=)done
anonymous
  • anonymous
thank u so much
anonymous
  • anonymous
can u help me with other similar ones i really want to get 100% on this test @Nnesha
Nnesha
  • Nnesha
sorry to say we are not allowed to help you on ur test its considered as cheating and if those questions are similar then now you should be able to solve i'm sorry good luck! trust on urself you will get 100% if you get C or D by your own that would be GREAT instead getting 100% with cheating sorry ;-;

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