## anonymous one year ago Given the following functions f(x) and g(x), solve f[g(6)] and select the correct answer below: f(x) = 6x + 12 g(x) = x − 8

1. triciaal

work from the inside find g(6) then use this value as the x in f(x)

2. anonymous

can u give me the first step please cuz am in a hurry and i need help with another question similar to this one

3. triciaal

|dw:1438011683998:dw|

4. triciaal

|dw:1438011729125:dw|

5. triciaal

what is the value for g(6) ?

6. anonymous

@Nnesha

7. triciaal

why are you being rude and ungrateful ? when you tag someone else while you are being helped and do not want to participate will not let you learn apparently you do not even want to answer what is 6 minus 8 . I have done the problem it would be to your advantage to read the responses and try rather than expect answers.

8. anonymous

i dont know any of this

9. anonymous

and am not being rude

10. Nnesha

hey same like last one so first you need to find g(6) as triciaal mentioned

11. anonymous

i dont get it

12. Nnesha

first deal with red part $f[\color{Red}{g(6)}]$ g(6) means x =6 so substitute x for 6 in g(x) function

13. anonymous

-2

14. Nnesha

yes right so g(6) = -2 so substitute x for -2 in f(x) function that's what they are asking f(g(6) =

15. anonymous

so the eguation would be f(x)=6(-2)+12

16. Nnesha

yep right

17. anonymous

f(x)=0

18. Nnesha

not f(x) f(g(6)) = 0

19. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @maria12vera so the eguation would be f(x)=6(-2)+12 $$\color{blue}{\text{End of Quote}}$$ it's f(g(6)) which is f(-2) you don't have to solve left side but better to show that what we are solving for so it's f(g(6)) = 0 :=)done

20. anonymous

thank u so much

21. anonymous

can u help me with other similar ones i really want to get 100% on this test @Nnesha

22. Nnesha

sorry to say we are not allowed to help you on ur test its considered as cheating and if those questions are similar then now you should be able to solve i'm sorry good luck! trust on urself you will get 100% if you get C or D by your own that would be GREAT instead getting 100% with cheating sorry ;-;