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anonymous

  • one year ago

HELP! with summation notation. will medal! (see attachment)

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    please please help with the first one

  3. anonymous
    • one year ago
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    Do you need to find the sum?

  4. anonymous
    • one year ago
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    yes @Nixy

  5. anonymous
    • one year ago
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    The first one is arithmetic so we can do the following First find the first and last terms by putting n= 1 and n = 50 \( \huge a_1 = 3(1) + 7 = 10\) 10 is your first. Now find the last \( \huge a_1 = 3(50) + 7 = 157\) Ok, next part coming. I am doing number 6

  6. anonymous
    • one year ago
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    Do you still need help?

  7. anonymous
    • one year ago
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    Now we use the formula \( \huge S_n = \frac{n}{2}(a_1+a_n) \) Now just plugin our numbers \( \huge S_{50} = \frac{50}{2}(10+157) \) \( \huge S_{50} = 4175\)

  8. anonymous
    • one year ago
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    is that the answer?? thats how you do it? @Nixy

  9. anonymous
    • one year ago
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    That is all the steps and the answer is 4175

  10. anonymous
    • one year ago
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    could you also help with 7? then ill do 8 and 9 by my self @Nixy

  11. anonymous
    • one year ago
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    @pooja195 please help with 7!!??

  12. anonymous
    • one year ago
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    Number 7 looks like the Sum of an Infinite Geometric Series

  13. anonymous
    • one year ago
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    if i do it will you check it?

  14. anonymous
    • one year ago
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    actually i have number 7 done but I dont understand 8

  15. anonymous
    • one year ago
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    i dont get how there is no number above the "e"

  16. anonymous
    • one year ago
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    @Nixy

  17. anonymous
    • one year ago
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    \( \huge \sum_{n=1}^{12} 2*4^n \) First you need to rewrite the series so it is in the form of \( \huge \sum_{n=1}^{12} a_1*r^{n-1} \) \( \huge \sum_{n=1}^{12} 8*4^{n-1} \) Now identify a_1 and r ? If |r| < 1 the series is converges and we need to find the sum if not it, there is no need to find the sum Sorry I am at work and that is why it is taking me a little bit of time.

  18. anonymous
    • one year ago
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    is this number 8? @Nixy

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