Perform this operation and report the answer to the correct number of significant figures: What is the mass of a cube of aluminum that is 4.0 cm on each edge? The density of aluminum is 2.7 g/cm3. Show all calculations leading to an answer.help me please
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
First step is to calculate the volume of the cube
V= lengh x width x height
We know each of these measurements are 4 cm so the volume is?
Once you find the volume you can then use the formula M=VD where M is the mass that you're trying to find, V is the volume you found in the first step and D is the density that is given
Rules when multiplying for significant figures are:
a) First perform all the operations, even if changing from one formula to another.
b) Round off the result so that it has the same number of sig figs as the least of all those used in your calculation.
Not the answer you are looking for? Search for more explanations.
2.Vcube = length*width*height Vcube = 4.0cm*4.0cm*4.0cm Vcube = 64cm^3 2.7g/cm^3 = m/64cm^3 m = 2.7g/cm^3*64cm^3 m = 172.8g is hat right
172.8 is the answer but that doesn't take sig figs into account
okay im totally lost
the two numbers have two significant digits therefore your answer can only have two significant figures
sorry can you explain more
The numbers given in the problem (4.0 cm and 2.7 g/cm^3) each have 2 significant figures.
And since the problem used multiplication, and not addition, the answer must also have 2 significant figures. Does that make sense?
If I had 6.00386 times 2.1 my answer would only have two significant digits because of the 2.1
Do you understand how to find the number of sig figs in a number?
Non-zero digits are always significant.
Any zeros between two significant digits are significant.
A final zero or trailing zeros in the decimal portion ONLY are significant.
6 is one sig fig
606 is 3 sig figs
0.006 is 1 sig fig
0.0060 is 2 sig figs
60 is 1 sig fig
I use these two rules for finding the number of sig figs:
When the decimal is present, start counting from the left side of the number with the first non-zero digit and count the rest of the digits. For example, 0.003040 has 4 sig figs.|dw:1438022288195:dw|
When the decimal is absent, start counting from the right with the first non-zero digit. For example, 604,000 has 3 sig figs.|dw:1438022384372:dw|
But @taramgrant0543664 's rules are also true just another way of looking at it. :-)