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anonymous
 one year ago
54,55,59,61,61,62,68,70,72 how do i find the irst quartile, median, third quartile, and maximum of the data set?
anonymous
 one year ago
54,55,59,61,61,62,68,70,72 how do i find the irst quartile, median, third quartile, and maximum of the data set?

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LynFran
 one year ago
Best ResponseYou've already chosen the best response.2the first quartile can be found using this formula \[\frac{ 1 }{ 4 }(n+1)\]

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2since there 9 #s in the set

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{ 1 }{ 4 }(9+1)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01 can't be divided by 4 can it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do i move the 9+1 over the 4.

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2u will get \[\frac{ 1 }{ 4 }(10)\]\[2.5th value\] the average 2nd and 3rd values are 55 and 59 so \[\frac{ 55+59 }{ 2 }=?\]

LynFran
 one year ago
Best ResponseYou've already chosen the best response.255+59/2=57 now 57 is ur 1st quartile value

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay. what is the 2.5th value?

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2thats the average where u will find ur two numbers for the fisrt quartile

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2so in this set of numbers the first quartile is between the the 2nd and 3rd #

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2so we add the 2nd and 3rd # and then divide the # by 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay would that be 54 and 55?

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2no thats the 1st and 2nd # ... u need the 2nd and 3rd #

LynFran
 one year ago
Best ResponseYou've already chosen the best response.259+55=114 now we divide by 2

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2good now 57 is ur 1st quartile

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2to find the median we located the middle value in the set....what # is in the middle?

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2to find the 3rd quartile the formula is \[\frac{ 3 }{ 4 }(n+1)th . value \]

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{ 3 }{ 4 }(9+1)th.value\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What do i do first add the 9+1 will give me 10 but what do i do next?

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{ 3 }{4 }(10)th.value\]\[\frac{ 30 }{ 4 }th. value\]7.5 th. value so the 3rd quartile is between the 7th and 8th numbers

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh so we time it by 3 3*10 = 30 /4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.07th and 8th what does that mean?

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2we locate the 7th and 8th #s in the data/set

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2whats the 7th and 8 number frm the set

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2good now add them and divide by 2

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2good thats ur 3rd quartile

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So we should be done.

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2here more info on quartiles with a similar example http://www.mathsteacher.com.au/year9/ch17_statistics/06_quartiles/quartiles.htm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks for the link too.

LynFran
 one year ago
Best ResponseYou've already chosen the best response.2the 2nd quatile \[\frac{ 2 }{ 4 }(10)th.value \]= 5th. value so the 5th value is 61 and yes 61 is the 2nd quartile
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