54,55,59,61,61,62,68,70,72 how do i find the irst quartile, median, third quartile, and maximum of the data set?

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54,55,59,61,61,62,68,70,72 how do i find the irst quartile, median, third quartile, and maximum of the data set?

Mathematics
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the first quartile can be found using this formula \[\frac{ 1 }{ 4 }(n+1)\]
n=9
9/4?

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Other answers:

since there 9 #s in the set
Okay
\[\frac{ 1 }{ 4 }(9+1)\]
1/4(9+1
1 can't be divided by 4 can it?
Do i move the 9+1 over the 4.
u will get \[\frac{ 1 }{ 4 }(10)\]\[2.5th value\] the average 2nd and 3rd values are 55 and 59 so \[\frac{ 55+59 }{ 2 }=?\]
Lagging
55+59/2=57 now 57 is ur 1st quartile value
Okay. what is the 2.5th value?
thats the average where u will find ur two numbers for the fisrt quartile
so in this set of numbers the first quartile is between the the 2nd and 3rd #
Okay
so we add the 2nd and 3rd # and then divide the # by 2
okay would that be 54 and 55?
no thats the 1st and 2nd # ... u need the 2nd and 3rd #
so 55 and 59?
yes now add them
100 +14 114
59+55=114 now we divide by 2
114/2=?
57
good now 57 is ur 1st quartile
Alright.
to find the median we located the middle value in the set....what # is in the middle?
61?
correct
to find the 3rd quartile the formula is \[\frac{ 3 }{ 4 }(n+1)th . value \]
\[\frac{ 3 }{ 4 }(9+1)th.value\]
What do i do first add the 9+1 will give me 10 but what do i do next?
\[\frac{ 3 }{4 }(10)th.value\]\[\frac{ 30 }{ 4 }th. value\]7.5 th. value so the 3rd quartile is between the 7th and 8th numbers
Oh so we time it by 3 3*10 = 30 /4
7th and 8th what does that mean?
we locate the 7th and 8th #s in the data/set
whats the 7th and 8 number frm the set
Okay.
68 and 70
good now add them and divide by 2
138/2 = 69
good thats ur 3rd quartile
So we should be done.
whats the maximum?
Not sure. ^ ^;
72..
DX Ahh.
Okay thanks.
here more info on quartiles with a similar example http://www.mathsteacher.com.au/year9/ch17_statistics/06_quartiles/quartiles.htm
welcome
Thanks for the link too.
the 2nd quatile \[\frac{ 2 }{ 4 }(10)th.value \]= 5th. value so the 5th value is 61 and yes 61 is the 2nd quartile
Alright thanks.

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