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Barrelracing
 one year ago
Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = 1.
f(x) = −one twelfth (x − 5)2 + 2
f(x) = one twelfth (x − 5)2 + 2
f(x) = −one twelfth (x + 5)2 + 2
f(x) = one twelfth (x + 5)2 + 2
Barrelracing
 one year ago
Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = 1. f(x) = −one twelfth (x − 5)2 + 2 f(x) = one twelfth (x − 5)2 + 2 f(x) = −one twelfth (x + 5)2 + 2 f(x) = one twelfth (x + 5)2 + 2

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im not good with directrix but i think it is d because this is what the graph looks like:dw:1438022849329:dw

Barrelracing
 one year ago
Best ResponseYou've already chosen the best response.0so which one is the answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think it is d. Is this FLVS?
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