anonymous
  • anonymous
You have a set of 10 cards—five red and five blue. Each group of five colored cards is numbered one through five. What is the probability of drawing a red four and then a blue four, while replacing the card between the drawings? A company has determined that 1% of its widgets are defective. If a customer received 2 widgets, what is the probability that they are both defective?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@jcoury
anonymous
  • anonymous
Do you know about the pigeonhole principle?
anonymous
  • anonymous
@OregonDuck

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OregonDuck
  • OregonDuck
the odds in drawing the red 4 is 1 in 10, so to get it would be 1/10. the odds are the same for getting the blue 4, so again, it's 1/10. Because this is a probability of two simultaneous events, you have to multiply the probabilities. So, (1/10)(1/10) = 1/100. Your answer is A.
anonymous
  • anonymous
Where did you get A from, i don't see any choices?
OregonDuck
  • OregonDuck
Assume independence because there are probably a lot of widgets. 1/100 x 1/100 = 1/10,000 How do I get the 1/100? From 1% 1% = 0.01 = 1/100
OregonDuck
  • OregonDuck
i have had this question before and before that choice was a so i thought i was a
anonymous
  • anonymous
wow
OregonDuck
  • OregonDuck
yup i am pretty fast
OregonDuck
  • OregonDuck
yeah all your catoriges have to move up for your mian number to change
anonymous
  • anonymous
how do i get more engagement?
OregonDuck
  • OregonDuck
i have not moved up in a while but i have answered so many questions and i found out i need 8 more medals
anonymous
  • anonymous
k
OregonDuck
  • OregonDuck
Your dedication and engagement when learning on OpenStudy

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