You have a set of 10 cards—five red and five blue. Each group of five colored cards is numbered one through five.
What is the probability of drawing a red four and then a blue four, while replacing the card between the drawings?
A company has determined that 1% of its widgets are defective.
If a customer received 2 widgets, what is the probability that they are both defective?
Stacey Warren - Expert brainly.com
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the odds in drawing the red 4 is 1 in 10, so to get it would be 1/10.
the odds are the same for getting the blue 4, so again, it's 1/10.
Because this is a probability of two simultaneous events, you have to multiply the probabilities.
So, (1/10)(1/10) = 1/100. Your answer is A.
Where did you get A from, i don't see any choices?
Assume independence because there are probably a lot of widgets.
1/100 x 1/100 = 1/10,000
How do I get the 1/100?
1% = 0.01 = 1/100
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i have not moved up in a while but i have answered so many questions and i found out i need 8 more medals
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