You have a set of 10 cards—five red and five blue. Each group of five colored cards is numbered one through five. What is the probability of drawing a red four and then a blue four, while replacing the card between the drawings? A company has determined that 1% of its widgets are defective. If a customer received 2 widgets, what is the probability that they are both defective?

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You have a set of 10 cards—five red and five blue. Each group of five colored cards is numbered one through five. What is the probability of drawing a red four and then a blue four, while replacing the card between the drawings? A company has determined that 1% of its widgets are defective. If a customer received 2 widgets, what is the probability that they are both defective?

Mathematics
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Do you know about the pigeonhole principle?

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the odds in drawing the red 4 is 1 in 10, so to get it would be 1/10. the odds are the same for getting the blue 4, so again, it's 1/10. Because this is a probability of two simultaneous events, you have to multiply the probabilities. So, (1/10)(1/10) = 1/100. Your answer is A.
Where did you get A from, i don't see any choices?
Assume independence because there are probably a lot of widgets. 1/100 x 1/100 = 1/10,000 How do I get the 1/100? From 1% 1% = 0.01 = 1/100
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