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anonymous

  • one year ago

You have a set of 10 cards—five red and five blue. Each group of five colored cards is numbered one through five. What is the probability of drawing a red four and then a blue four, while replacing the card between the drawings? A company has determined that 1% of its widgets are defective. If a customer received 2 widgets, what is the probability that they are both defective?

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  1. anonymous
    • one year ago
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    @jcoury

  2. anonymous
    • one year ago
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    Do you know about the pigeonhole principle?

  3. anonymous
    • one year ago
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    @OregonDuck

  4. OregonDuck
    • one year ago
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    the odds in drawing the red 4 is 1 in 10, so to get it would be 1/10. the odds are the same for getting the blue 4, so again, it's 1/10. Because this is a probability of two simultaneous events, you have to multiply the probabilities. So, (1/10)(1/10) = 1/100. Your answer is A.

  5. anonymous
    • one year ago
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    Where did you get A from, i don't see any choices?

  6. OregonDuck
    • one year ago
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    Assume independence because there are probably a lot of widgets. 1/100 x 1/100 = 1/10,000 How do I get the 1/100? From 1% 1% = 0.01 = 1/100

  7. OregonDuck
    • one year ago
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    i have had this question before and before that choice was a so i thought i was a

  8. anonymous
    • one year ago
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    wow

  9. OregonDuck
    • one year ago
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    yup i am pretty fast

  10. OregonDuck
    • one year ago
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    yeah all your catoriges have to move up for your mian number to change

  11. anonymous
    • one year ago
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    how do i get more engagement?

  12. OregonDuck
    • one year ago
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    i have not moved up in a while but i have answered so many questions and i found out i need 8 more medals

  13. anonymous
    • one year ago
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    k

  14. OregonDuck
    • one year ago
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    Your dedication and engagement when learning on OpenStudy

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spraguer (Moderator)
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