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anonymous

  • one year ago

Adding, Subtracting, Multiplying, and Dividing Functions. Can someone help me with this subject

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  1. anonymous
    • one year ago
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    I might be able to but depends on the question though

  2. anonymous
    • one year ago
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    k

  3. anonymous
    • one year ago
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    Two neighboring towns, Nash Town and Bay Town, were surveyed, and their populations were found to be x1/3 +2x1/5 and 3x1/3 - x1/5 (in thousands), respectively, where x is the number of years since the towns were founded. (Assume that both towns were founded at the same time.)

  4. anonymous
    • one year ago
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    Question 1 Find the function that gives the total population of both towns.

  5. anonymous
    • one year ago
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    @Anna-Rose , @Arn.01 , @nincompoop, @BioHazard9064

  6. anonymous
    • one year ago
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    @Barrelracing, @freegirl11112, @iloveyou;*, @jaredhm29, @Nnesha, @Tashiya_Pandas

  7. anonymous
    • one year ago
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    sorry i suck at math :/

  8. anonymous
    • one year ago
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    its alright

  9. BioHazard9064
    • one year ago
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    merda

  10. BioHazard9064
    • one year ago
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    Due città vicine , Nash città e sulla baia di Città , sono state intervistate , e le loro popolazioni sono risultati x1 / 3 + ​​2x1 / 5 e 3x1 / 3 - x1 / 5 (in migliaia ), rispettivamente, dove x è il numero di anni da quando le città sono state fondate . ( Si supponga che entrambe le città sono state fondate allo stesso tempo . )

  11. anonymous
    • one year ago
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    did youjust translate that

  12. BioHazard9064
    • one year ago
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  13. anonymous
    • one year ago
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    por que

  14. BioHazard9064
    • one year ago
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    perché

  15. BioHazard9064
    • one year ago
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    ok

  16. BioHazard9064
    • one year ago
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    Did you try google

  17. BioHazard9064
    • one year ago
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    nvm

  18. BioHazard9064
    • one year ago
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    @LynFran Puoi Aiutare

  19. BioHazard9064
    • one year ago
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    I dont know

  20. BioHazard9064
    • one year ago
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    scusate - sorry

  21. BioHazard9064
    • one year ago
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    Two neighboring towns, Nash Town and Bay Town, were surveyed, and their populations were found to be x1/3 +2x1/5 and 3x1/3 - x1/5 (in thousands), respectively, where x is the number of years since the towns were founded. (Assume that both towns were founded at the same time.)

  22. BioHazard9064
    • one year ago
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    ok so lets break it down a little what do we need to know and what we dont

  23. anonymous
    • one year ago
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    sorry @BioHazard9064 cant help

  24. BioHazard9064
    • one year ago
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    its ok

  25. BioHazard9064
    • one year ago
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    So Nash Town would be x1/3 +2x1/5 and (in thousands) Bay Town 3x1/3 - x1/5 And x = years

  26. BioHazard9064
    • one year ago
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    after that i dont know

  27. Jacob902
    • one year ago
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    Example Problem f(x) = 2x g(x) = 3x+1 What is f(3) + g(4) ? Step 1: evaluate the individual functions f(3) = 2×3 = 6 g(4) = 3×4 +1 = 13 Step 2: Add the values that your functions produced f(3) + g(4) = 6 + 13 = 19

  28. anonymous
    • one year ago
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    @dan815

  29. anonymous
    • one year ago
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    @ganeshie8

  30. anonymous
    • one year ago
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    @nincompoop

  31. dan815
    • one year ago
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    okay so

  32. dan815
    • one year ago
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    i think the main operation to understand here is addition the rest stem from it

  33. dan815
    • one year ago
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    lets start with a simple example okay now u know the way they teach u about adding 2 numbers 111 +234 ------ 345 They teach you to add by column, and carry when u pass 10

  34. dan815
    • one year ago
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    are you with me so far

  35. anonymous
    • one year ago
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    yes

  36. dan815
    • one year ago
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    now why column by column its because u can also think about it like adding 'like' terms

  37. dan815
    • one year ago
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    you are adding the 1s units, the 10s units and 100s units together

  38. anonymous
    • one year ago
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    i need help putting it in an equation then i can solve it

  39. dan815
    • one year ago
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    in otherwords \[111+234= (100+10+1) + (200+30+4)\\ =(1*10^2+1*10^1+1*10^0) +(2*10^2+3*10^1+4*10^0)\] now you add these like terms like so \[1*10^2+2*10^2 + 1*10^1 + 3*10^1+1*10^0+4*10^0\\ =(1+2)*10^2+(1+3)*10^1+(1+4)*10^0\] this is very analogous to what polynomial addition instead of 10, wwe have x there

  40. anonymous
    • one year ago
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    oh thx

  41. anonymous
    • one year ago
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    oh thx

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