Adding, Subtracting, Multiplying, and Dividing Functions. Can someone help me with this subject

- anonymous

Adding, Subtracting, Multiplying, and Dividing Functions. Can someone help me with this subject

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- chestercat

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- anonymous

I might be able to but depends on the question though

- anonymous

k

- anonymous

Two neighboring towns, Nash Town and Bay Town, were surveyed, and their populations were found to be x1/3 +2x1/5 and 3x1/3 - x1/5 (in thousands), respectively, where x is the number of years since the towns were founded. (Assume that both towns were founded at the same time.)

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## More answers

- anonymous

Question 1
Find the function that gives the total population of both towns.

- anonymous

@Anna-Rose , @Arn.01 , @nincompoop, @BioHazard9064

- anonymous

@Barrelracing, @freegirl11112, @iloveyou;*, @jaredhm29, @Nnesha, @Tashiya_Pandas

- anonymous

sorry i suck at math :/

- anonymous

its alright

- BioHazard9064

merda

- BioHazard9064

Due città vicine , Nash città e sulla baia di Città , sono state intervistate , e le loro popolazioni sono risultati x1 / 3 + 2x1 / 5 e 3x1 / 3 - x1 / 5 (in migliaia ), rispettivamente, dove x è il numero di anni da quando le città sono state fondate . ( Si supponga che entrambe le città sono state fondate allo stesso tempo . )

- anonymous

did youjust translate that

- BioHazard9064

sì

- anonymous

por que

- BioHazard9064

perché

- BioHazard9064

ok

- BioHazard9064

Did you try google

- BioHazard9064

nvm

- BioHazard9064

@LynFran Puoi Aiutare

- BioHazard9064

I dont know

- BioHazard9064

scusate - sorry

- BioHazard9064

- BioHazard9064

ok so lets break it down a little what do we need to know and what we dont

- anonymous

sorry @BioHazard9064 cant help

- BioHazard9064

its ok

- BioHazard9064

So Nash Town would be x1/3 +2x1/5 and
(in thousands)
Bay Town 3x1/3 - x1/5
And x = years

- BioHazard9064

after that i dont know

- Jacob902

Example Problem
f(x) = 2x
g(x) = 3x+1
What is f(3) + g(4) ?
Step 1: evaluate the individual functions
f(3) = 2×3 = 6
g(4) = 3×4 +1 = 13
Step 2: Add the values that your functions produced
f(3) + g(4) = 6 + 13 = 19

- anonymous

@dan815

- anonymous

@ganeshie8

- anonymous

@nincompoop

- dan815

okay so

- dan815

i think the main operation to understand here is addition the rest stem from it

- dan815

lets start with a simple example okay
now u know the way they teach u about adding 2 numbers
111
+234
------
345
They teach you to add by column, and carry when u pass 10

- dan815

are you with me so far

- anonymous

yes

- dan815

now why column by column its because u can also think about it like adding 'like' terms

- dan815

you are adding the 1s units, the 10s units and 100s units together

- anonymous

i need help putting it in an equation then i can solve it

- dan815

in otherwords
\[111+234= (100+10+1) + (200+30+4)\\
=(1*10^2+1*10^1+1*10^0) +(2*10^2+3*10^1+4*10^0)\]
now you add these like terms like so
\[1*10^2+2*10^2 + 1*10^1 + 3*10^1+1*10^0+4*10^0\\
=(1+2)*10^2+(1+3)*10^1+(1+4)*10^0\]
this is very analogous to what polynomial addition
instead of 10, wwe have x there

- anonymous

oh thx

- anonymous

oh thx

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