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anonymous
 one year ago
Adding, Subtracting, Multiplying, and Dividing Functions. Can someone help me with this subject
anonymous
 one year ago
Adding, Subtracting, Multiplying, and Dividing Functions. Can someone help me with this subject

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I might be able to but depends on the question though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Two neighboring towns, Nash Town and Bay Town, were surveyed, and their populations were found to be x1/3 +2x1/5 and 3x1/3  x1/5 (in thousands), respectively, where x is the number of years since the towns were founded. (Assume that both towns were founded at the same time.)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Question 1 Find the function that gives the total population of both towns.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@AnnaRose , @Arn.01 , @nincompoop, @BioHazard9064

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Barrelracing, @freegirl11112, @iloveyou;*, @jaredhm29, @Nnesha, @Tashiya_Pandas

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry i suck at math :/

BioHazard9064
 one year ago
Best ResponseYou've already chosen the best response.0Due città vicine , Nash città e sulla baia di Città , sono state intervistate , e le loro popolazioni sono risultati x1 / 3 + 2x1 / 5 e 3x1 / 3  x1 / 5 (in migliaia ), rispettivamente, dove x è il numero di anni da quando le città sono state fondate . ( Si supponga che entrambe le città sono state fondate allo stesso tempo . )

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0did youjust translate that

BioHazard9064
 one year ago
Best ResponseYou've already chosen the best response.0Did you try google

BioHazard9064
 one year ago
Best ResponseYou've already chosen the best response.0@LynFran Puoi Aiutare

BioHazard9064
 one year ago
Best ResponseYou've already chosen the best response.0Two neighboring towns, Nash Town and Bay Town, were surveyed, and their populations were found to be x1/3 +2x1/5 and 3x1/3  x1/5 (in thousands), respectively, where x is the number of years since the towns were founded. (Assume that both towns were founded at the same time.)

BioHazard9064
 one year ago
Best ResponseYou've already chosen the best response.0ok so lets break it down a little what do we need to know and what we dont

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry @BioHazard9064 cant help

BioHazard9064
 one year ago
Best ResponseYou've already chosen the best response.0So Nash Town would be x1/3 +2x1/5 and (in thousands) Bay Town 3x1/3  x1/5 And x = years

BioHazard9064
 one year ago
Best ResponseYou've already chosen the best response.0after that i dont know

Jacob902
 one year ago
Best ResponseYou've already chosen the best response.0Example Problem f(x) = 2x g(x) = 3x+1 What is f(3) + g(4) ? Step 1: evaluate the individual functions f(3) = 2×3 = 6 g(4) = 3×4 +1 = 13 Step 2: Add the values that your functions produced f(3) + g(4) = 6 + 13 = 19

dan815
 one year ago
Best ResponseYou've already chosen the best response.1i think the main operation to understand here is addition the rest stem from it

dan815
 one year ago
Best ResponseYou've already chosen the best response.1lets start with a simple example okay now u know the way they teach u about adding 2 numbers 111 +234  345 They teach you to add by column, and carry when u pass 10

dan815
 one year ago
Best ResponseYou've already chosen the best response.1now why column by column its because u can also think about it like adding 'like' terms

dan815
 one year ago
Best ResponseYou've already chosen the best response.1you are adding the 1s units, the 10s units and 100s units together

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i need help putting it in an equation then i can solve it

dan815
 one year ago
Best ResponseYou've already chosen the best response.1in otherwords \[111+234= (100+10+1) + (200+30+4)\\ =(1*10^2+1*10^1+1*10^0) +(2*10^2+3*10^1+4*10^0)\] now you add these like terms like so \[1*10^2+2*10^2 + 1*10^1 + 3*10^1+1*10^0+4*10^0\\ =(1+2)*10^2+(1+3)*10^1+(1+4)*10^0\] this is very analogous to what polynomial addition instead of 10, wwe have x there
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