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anonymous

  • one year ago

10√x5•x4•x2 simply

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  1. anonymous
    • one year ago
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    @OregonDuck

  2. DanJS
    • one year ago
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    those are powers right

  3. anonymous
    • one year ago
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    yes

  4. DanJS
    • one year ago
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    \[10\sqrt{x^5}* x^4 *x^2\]

  5. DanJS
    • one year ago
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    is the 5 under the root or outside

  6. anonymous
    • one year ago
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    yes

  7. DanJS
    • one year ago
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    remember \[\sqrt{x} = x ^{1/2}\]

  8. DanJS
    • one year ago
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    also remember, a power raised to a power, you multiply them together... \[[x^{a}]^b = x^{a*b}\]

  9. DanJS
    • one year ago
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    and lastly, remember, multiplying a base raised to two powers, you ADD them \[x^a * x^b = x^{a+b}\]

  10. DanJS
    • one year ago
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    so, with those notes, can you start it

  11. anonymous
    • one year ago
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    i got x = 5

  12. DanJS
    • one year ago
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    you cant solve for x, it is not an equation, just make it look different, simpler

  13. anonymous
    • one year ago
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    x^ 10/11

  14. DanJS
    • one year ago
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    ...ill show you step by step

  15. DanJS
    • one year ago
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    For the first root term \[10\sqrt{x^5} = 10[x ^{5}]^{1/2} = 10x^{5*1/2} = 10x^{5/2}\]

  16. DanJS
    • one year ago
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    Then when multiplying that by x^4 and x^2 you add the exponents \[10x^{5/2}*x^4*x^2 = 10x^{5/2+4+2}\]

  17. DanJS
    • one year ago
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    so i got \[10x^{17/2}\]

  18. DanJS
    • one year ago
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    you just have to remember the three or so basic exponent rules, then you can do all the probs

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