anonymous
  • anonymous
help please! :)
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
anonymous
  • anonymous
where is the question?
anonymous
  • anonymous

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anonymous
  • anonymous
what was step 4 again?
anonymous
  • anonymous
the complete answer?
anonymous
  • anonymous
Width =2 x 10 =20 Height = 12 x 10 =120 Length = 8 x 10 =80 2 x W x H + 2 x L x W + 2 x H x L = 27,200 So the surface are of the box is 27,200. is that the full answer for step 4?
Vocaloid
  • Vocaloid
yes
anonymous
  • anonymous
but its not asking for the surface area
Vocaloid
  • Vocaloid
yes it is, please read the question again...
anonymous
  • anonymous
oh yea sorry :(
anonymous
  • anonymous
@Vocaloid can you make sure im not missing anything?
anonymous
  • anonymous
1. List the dimensions of your box. Be sure to include the units (in, cm, ft, etc.). The dimensions of my box are: Width = 2 inches Height = 12 inches Length = 8 inches 2. Describe the shape of the cross section when the box is cut parallel to the base. The shape of the cross section when the box is cut parallel to the base is a rectangle. 3. Width = 2 inches Height = 12 inches Length = 8 inches 2 x W x H + 2 x L x W + 2 x H x L = 272 So the surface area of the box is 272. 4. Width =2 x 10 =20 Height = 12 x 10 =120 Length = 8 x 10 =80 2 x W x H + 2 x L x W + 2 x H x L = 27,200 So the surface are of the box is 27,200. 5. Width = 2 inches Height = 12 inches Length = 8 inches Volume = 2 x 12 x 8 = 192 So the volume of the box is 192. 6. Width = 2÷10=0.2 Height = 12÷10=1.2 Length = 8÷10=0.8 Volume = 0.2x1.2x0.8 = 0.192 So the volume of the box if it is scaled down by a factor of 1/10 is 0.192.
Vocaloid
  • Vocaloid
right
Vocaloid
  • Vocaloid
everything looks ok
anonymous
  • anonymous
you read everything already
anonymous
  • anonymous
can you make sure please
Vocaloid
  • Vocaloid
the only thing I would possibly add is units 1. List the dimensions of your box. Be sure to include the units (in, cm, ft, etc.). The dimensions of my box are: Width = 2 inches Height = 12 inches Length = 8 inches 2. Describe the shape of the cross section when the box is cut parallel to the base. The shape of the cross section when the box is cut parallel to the base is a rectangle. 3. Width = 2 inches Height = 12 inches Length = 8 inches 2 x W x H + 2 x L x W + 2 x H x L = 272 So the surface area of the box is 272 in^2 4. Width =2 x 10 =20 Height = 12 x 10 =120 Length = 8 x 10 =80 2 x W x H + 2 x L x W + 2 x H x L = 27,200 So the surface are of the box is 27,200 in^2 5. Width = 2 inches Height = 12 inches Length = 8 inches Volume = 2 x 12 x 8 = 192 So the volume of the box is 192 in^3 6. Width = 2÷10=0.2 Height = 12÷10=1.2 Length = 8÷10=0.8 Volume = 0.2x1.2x0.8 = 0.192 So the volume of the box if it is scaled down by a factor of 1/10 is 0.192 in^3

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