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GucciDoTheDishes
 one year ago
**medal and fan
Simplify: (sin Θ − cos Θ)2 + (sin Θ + cos Θ)2
GucciDoTheDishes
 one year ago
**medal and fan Simplify: (sin Θ − cos Θ)2 + (sin Θ + cos Θ)2

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guccidothedishes
 one year ago
Best ResponseYou've already chosen the best response.0answer choices A) 1 B) 2 C)sin^2Θ D)cos^2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1let sin theta = x cos theta = y so you have \[\huge\rm (xy)^2 +(x +y)^2\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1(xy)^2 is same as (xy)(xy) apply foil method

guccidothedishes
 one year ago
Best ResponseYou've already chosen the best response.0so it cancels out ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1no there is a plus sign

guccidothedishes
 one year ago
Best ResponseYou've already chosen the best response.0im not really familiar with the foil method

guccidothedishes
 one year ago
Best ResponseYou've already chosen the best response.0do I just multiply (xy)(xy) ??

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1ohh okay dw:1438028749837:dw multiply first and 2nd term of first parentheses by 2nd parentheses

guccidothedishes
 one year ago
Best ResponseYou've already chosen the best response.0I know part of it is X^2 so x &y multiplied its just x*y ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right but don't forget the negative sign \[\huge\rm (xy)(xy)\] dw:1438029051942:dw

guccidothedishes
 one year ago
Best ResponseYou've already chosen the best response.0okay but now whats the next step to the problem ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1now multiply 2nd parentheses by 2nd term of 1st parenthesesdw:1438029177493:dw

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1well no little mistake y times y = ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm\color{reD}{ (xy)^2} +(x +y)^2\] \[\huge\rm \color{Red}{x^2xyxy+y^2} +(x+y)^2\] combine like terms and then foil (x+y)^2

guccidothedishes
 one year ago
Best ResponseYou've already chosen the best response.0xy and xy are like terms do they cancel out ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1no you need to be careful abt signs xy xy you would cancel out if there are opposite signs xy xy = ? add example 11=2

guccidothedishes
 one year ago
Best ResponseYou've already chosen the best response.0but I would add them together correct ?

guccidothedishes
 one year ago
Best ResponseYou've already chosen the best response.0So i would get 2xy ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yep right now multiply (x+y)^2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1(x+y)^2 is same as (X+y)(x+y)

guccidothedishes
 one year ago
Best ResponseYou've already chosen the best response.0okay so now i ditribute xy^2 to x^2 + (x+y)^2+y^2?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1Have you expanded (x+y)^2 ? \[\huge\rm \color{Red}{x^2xyxy+y^2} +(x+y)^2\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1(x+y)^2 is the same as (x+y)(x+y) multiply this out

freckles
 one year ago
Best ResponseYou've already chosen the best response.1x(x+y)+y(x+y) use distributive property twice

guccidothedishes
 one year ago
Best ResponseYou've already chosen the best response.0so Im going to distribute the x to whats in parentheses and then do the same with the y , correct ?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1yes that is the distributive property it says a(b+c)=ab+ac

guccidothedishes
 one year ago
Best ResponseYou've already chosen the best response.0okay after distributing I got x^2+xy + yx+y^2

freckles
 one year ago
Best ResponseYou've already chosen the best response.1if have an apple and find another apple do you have a square amount of apples or just 2 apples?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1(x+y)^2=x^2+2xy+y^2 and (xy)^2=x^22xy+y^2

freckles
 one year ago
Best ResponseYou've already chosen the best response.1also recall sin^2(u)+cos^2(u)=1

freckles
 one year ago
Best ResponseYou've already chosen the best response.1anyways let us know if you need further help on this one

guccidothedishes
 one year ago
Best ResponseYou've already chosen the best response.0but I still dont get it lol sorry , what would the next step be ?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1recall you started with \[(\sin(\theta)+\cos(\theta))^2+(\sin(\theta)\cos(\theta))^2 \\ \text{ then you expanded} \\ \sin^2(\theta)+2\sin(\theta)\cos(\theta)+\cos^2(\theta)+\sin^2(\theta)2\sin(\theta)\cos(\theta)+\cos^2(\theta)\] are you not sure what sin^2(theta)+cos^2(theta) equals ? or is it you don't know what 2sin(theta)cos(theta)2sin(theta)cos(theta) is?

guccidothedishes
 one year ago
Best ResponseYou've already chosen the best response.0im not sure what it equals

freckles
 one year ago
Best ResponseYou've already chosen the best response.1sin^2(theta)+cos^2(theta)? or the same thing  the same thing?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1the first one is a Pythagorean identity sin^2(u)+cos^2(u)=1 the second one is using the additive inverse property that is u+(u)=0 or this could be written as uu=0 which should make since because if you have exactly one apple and so one takes that apple away you have no apples aka 0 apples

guccidothedishes
 one year ago
Best ResponseYou've already chosen the best response.0okay thank you
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