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anonymous

  • one year ago

The cost in dollars of producing x units of a particular brand of notebook is C(x) = x^2 – 400. a)Find the average rate of change of C with respect to x when the production level is changed from x = 100 to x = 102. Include units in your answer. b)Find the instantaneous rate of change of C with respect to x when x = 100. Include units in your answer.

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  1. anonymous
    • one year ago
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    really could use some help on this on !!!

  2. anonymous
    • one year ago
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    How do you think you should approach this? what do the terms average and instantaneous mean to you?

  3. anonymous
    • one year ago
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    well i understand the meaning of the terms im just not too sure how to go about obtaining them, for starters on problem a i know the formula but after i have the equation of the average rate of change what do i do?

  4. anonymous
    • one year ago
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    im getting (x^2 -9604)/(x-102) for the average rate of change equation

  5. anonymous
    • one year ago
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    \[average= \frac{ \Delta Y }{ \Delta X }\] You need to solve for Y at each X and then use this equation

  6. anonymous
    • one year ago
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    solve for y where ?!?

  7. anonymous
    • one year ago
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    eabollich

  8. anonymous
    • one year ago
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    C(x) is another way of writing Y in the equation of a line y=mx +b. Are you familiar with this equation?

  9. anonymous
    • one year ago
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    yes

  10. anonymous
    • one year ago
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    c(100) = 9600 c(102) = 10004 so... (9600-10004)/(100 - 102)?

  11. anonymous
    • one year ago
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    Yes. the negative signs cancel out. the traditional way would be to put 10004-9600 and 102-100 but as long as you are consistent, it doesn't make a difference

  12. anonymous
    • one year ago
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    Is this for calculus or algebra?

  13. anonymous
    • one year ago
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    calculus ab

  14. anonymous
    • one year ago
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    and im starting to think this is wrong

  15. anonymous
    • one year ago
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    http://home.earthlink.net/~peggyfrisbie/images/avg%20rate%20of%20change%20back.jpg The average rate of change is the same for calculus and algebra. The instantaneous rate is where things are easier if you are using calculus. http://www.thebestschools.org/wp-content/uploads/2014/08/calculus2.jpg

  16. anonymous
    • one year ago
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    Why do you think it is wrong?

  17. anonymous
    • one year ago
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    because we didn't use an equation i was certain would be relevant

  18. anonymous
    • one year ago
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    oh wait

  19. anonymous
    • one year ago
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    you just proved me wrong :p

  20. anonymous
    • one year ago
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    I changed the variables to X and Y but it is the same equation :)

  21. anonymous
    • one year ago
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    okay and for part b do i just find the derivative at that point?

  22. anonymous
    • one year ago
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    I assumed at first that it was an algebra class so I used X and Y, sorry for the confusion

  23. anonymous
    • one year ago
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    I haven't taken Calculus but I assume from what I am reading that you are correct. The third example on this website gives a good example of what that looks like: http://www.millersville.edu/~bikenaga/calculus/tangent/tangent.html

  24. anonymous
    • one year ago
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    thank's !!

  25. anonymous
    • one year ago
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    You're welcome! Glad I could help!

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