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anonymous
 one year ago
The cost in dollars of producing x units of a particular brand of notebook is C(x) = x^2 – 400.
a)Find the average rate of change of C with respect to x when the production level is changed from x = 100 to x = 102. Include units in your answer.
b)Find the instantaneous rate of change of C with respect to x when x = 100. Include units in your answer.
anonymous
 one year ago
The cost in dollars of producing x units of a particular brand of notebook is C(x) = x^2 – 400. a)Find the average rate of change of C with respect to x when the production level is changed from x = 100 to x = 102. Include units in your answer. b)Find the instantaneous rate of change of C with respect to x when x = 100. Include units in your answer.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0really could use some help on this on !!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do you think you should approach this? what do the terms average and instantaneous mean to you?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well i understand the meaning of the terms im just not too sure how to go about obtaining them, for starters on problem a i know the formula but after i have the equation of the average rate of change what do i do?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im getting (x^2 9604)/(x102) for the average rate of change equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[average= \frac{ \Delta Y }{ \Delta X }\] You need to solve for Y at each X and then use this equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0solve for y where ?!?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0C(x) is another way of writing Y in the equation of a line y=mx +b. Are you familiar with this equation?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0c(100) = 9600 c(102) = 10004 so... (960010004)/(100  102)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes. the negative signs cancel out. the traditional way would be to put 100049600 and 102100 but as long as you are consistent, it doesn't make a difference

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is this for calculus or algebra?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and im starting to think this is wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0http://home.earthlink.net/~peggyfrisbie/images/avg%20rate%20of%20change%20back.jpg The average rate of change is the same for calculus and algebra. The instantaneous rate is where things are easier if you are using calculus. http://www.thebestschools.org/wpcontent/uploads/2014/08/calculus2.jpg

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Why do you think it is wrong?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because we didn't use an equation i was certain would be relevant

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you just proved me wrong :p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I changed the variables to X and Y but it is the same equation :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay and for part b do i just find the derivative at that point?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I assumed at first that it was an algebra class so I used X and Y, sorry for the confusion

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I haven't taken Calculus but I assume from what I am reading that you are correct. The third example on this website gives a good example of what that looks like: http://www.millersville.edu/~bikenaga/calculus/tangent/tangent.html

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You're welcome! Glad I could help!
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