anonymous
  • anonymous
Reducing the volume of a contained gas by one third, while holding temperature constant, causes pressure to A. be decreased by two thirds. B. be increased by two thirds. C. be decreased by one third. D. be increased by one third
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Photon336
  • Photon336
Start with \[Pv = nRT\]
Photon336
  • Photon336
You keep the temperature constant, as well as the number of moles so nRT = a constant
Photon336
  • Photon336
\[Pv = k \]

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Photon336
  • Photon336
Then you want to know how a change in volume will affect the pressure
Photon336
  • Photon336
\[P _{1}V _{1} = P _{2}V _{2}\] this is what you get now
anonymous
  • anonymous
yeah......... im not understanding that @Photon336
Photon336
  • Photon336
may have to think about it this way |dw:1438032347186:dw| which one has the greater volume?
anonymous
  • anonymous
A
Photon336
  • Photon336
a bigger volume means that the (gas) has more space to move around
Photon336
  • Photon336
and think of pressure as the amount of times that the gas molecules hit the walls of the container.
Photon336
  • Photon336
if something has a bigger volume, that's more space so what happens to pressure?
Photon336
  • Photon336
|dw:1438032627030:dw| with that said which container would have more pressure if the number if we keep the amount of gas the same?
Photon336
  • Photon336
@coniquee ?

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