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anonymous
 one year ago
What are the domain of these two functions:
anonymous
 one year ago
What are the domain of these two functions:

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[y=3\sec(\pi2x)+5\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0somebody please help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Domain represents the value for x thus in the second equation is there any value that x cannot be?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the sine curve has its domain unrestricted where as the secant function has vertical asymptotes, hence a restricted domain.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0therefore the domain for the first function is (infinity,infinity)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but I do not know the domain for the second function, what is it? @Deeezzzz

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are you familiar with finding the period of the secant func?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The period of the second function is 2

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0The first function uses the secant function. Remember this identity. \(\sec \theta = \dfrac{1}{\cos \theta}\) The secant is not defined where the cosine equals zero.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0In the second function, you have the sine function. The sine function is defined for every value of theta.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait, so for the second function the domain is (infinity,infinity)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I still dont get the domain for the first function

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0There is no restriction on the domain of the sine function.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how would i write it down in terms of interval notation

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Where is the cosine equal to zero?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0The figure below shows where the cosine equals zero. It is at those points where the secant is undefined. dw:1438040478384:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0The first function has a secant, so its domain is all reals except for integer multiples of \(\dfrac{\pi}{2} \).
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