- anonymous

What are the domain of these two functions:

- schrodinger

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- anonymous

\[y=-3\sec(\pi-2x)+5\]

- anonymous

\[y=-2\sin(5/4x)\]

- anonymous

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## More answers

- anonymous

somebody please help

- anonymous

- anonymous

Domain represents the value for x thus in the second equation is there any value that x cannot be?

- anonymous

the sine curve has its domain unrestricted where as the secant function has vertical asymptotes, hence a restricted domain.

- anonymous

therefore the domain for the first function is (-infinity,infinity)

- anonymous

but I do not know the domain for the second function, what is it? @Deeezzzz

- anonymous

Are you familiar with finding the period of the secant func?

- anonymous

yes

- anonymous

The period of the second function is 2

- anonymous

- mathstudent55

The first function uses the secant function. Remember this identity.
\(\sec \theta = \dfrac{1}{\cos \theta}\)
The secant is not defined where the cosine equals zero.

- mathstudent55

In the second function, you have the sine function.
The sine function is defined for every value of theta.

- anonymous

wait, so for the second function the domain is (-infinity,infinity)

- mathstudent55

yes

- anonymous

I still dont get the domain for the first function

- mathstudent55

There is no restriction on the domain of the sine function.

- anonymous

how would i write it down in terms of interval notation

- mathstudent55

Where is the cosine equal to zero?

- anonymous

its undefined?

- anonymous

- mathstudent55

The figure below shows where the cosine equals zero.
It is at those points where the secant is undefined.
|dw:1438040478384:dw|

- mathstudent55

The first function has a secant, so its domain is all reals except for integer multiples of \(\dfrac{\pi}{2} \).

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