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anonymous

  • one year ago

Which of the following options is an equivalent function to f(x) = 3(2)3x?

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  1. anonymous
    • one year ago
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    Answers: f(x) = 3(8)x f(x) = 24x f(x) = 27(8)x f(x) = 3(8x)

  2. anonymous
    • one year ago
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    @Vocaloid

  3. DanJS
    • one year ago
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    none

  4. anonymous
    • one year ago
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    @DanJS what do u mean

  5. anonymous
    • one year ago
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    @Vocaloid

  6. anonymous
    • one year ago
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    @Saiyan @CBARREDO1 @Vocaloid please help

  7. anonymous
    • one year ago
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    @Saiyan

  8. DanJS
    • one year ago
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    As typed, you have f(x) = 3 * 2 * 3*x = 18x no way to get any of those answers with that...

  9. anonymous
    • one year ago
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    @DanJS sry its 3(2)^3x

  10. CBARREDO1
    • one year ago
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    f(x)= 3(8x)

  11. anonymous
    • one year ago
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    |dw:1438038522974:dw|

  12. CBARREDO1
    • one year ago
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    The answer is f(x)= 3(8x)

  13. anonymous
    • one year ago
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    @DanJS

  14. CBARREDO1
    • one year ago
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    THE ANSWER IS: f(x)= 3(8x)

  15. anonymous
    • one year ago
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    to the power of 3x

  16. anonymous
    • one year ago
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    3(2)^3x

  17. CBARREDO1
    • one year ago
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    @jaredhm29 THE ANSWER IS: f(x)= 3(8x)

  18. anonymous
    • one year ago
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    XD

  19. anonymous
    • one year ago
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    it is A \[ 3(8)^x\]

  20. CBARREDO1
    • one year ago
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    What have I been saying?!

  21. anonymous
    • one year ago
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    Which of the following options results in a graph that shows exponential decay? f(x) = 0.6(2)x f(x) = 3(0.7)x f(x) = 0.4(1.6)x f(x) = 20(3)x

  22. mathstudent55
    • one year ago
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    \(f(x) = 3(2)^{3x}\) Rule: To raise a power to a power, multiply powers. \(\large (a^m)^n = a^{mn}\) \(\large f(x) = 3(2)^{3x}\) Apply the rule above in reverse to \(2^{3x} \) \(\large f(x) = 3(2^3)^x\) \(\large f(x) = 3 \cdot 8^x \)

  23. anonymous
    • one year ago
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    Can u help Which of the following options results in a graph that shows exponential decay? f(x) = 0.6(2)x f(x) = 3(0.7)x f(x) = 0.4(1.6)x f(x) = 20(3)x @mathstudent55

  24. CBARREDO1
    • one year ago
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    f(x) = 3(0.7)x

  25. anonymous
    • one year ago
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    Which of the following options results in a graph that shows exponential growth? f(x) = 0.4(3)x f(x) = 3(0.5)x f(x) = 0.8(0.9)x f(x) = 0.9(5)−x

  26. CBARREDO1
    • one year ago
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    f(x) = 0.4(3)x

  27. anonymous
    • one year ago
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    For f(x) = 0.01(2)x, find the average rate of change from x = 3 to x = 8. 0.08 0.496 2.48 5

  28. anonymous
    • one year ago
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    @CBARREDO1

  29. mathstudent55
    • one year ago
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    \(\large f(x) = ak^x\) As exponents become larger, If \(k \gt 1\), it is exponential growth. If \(0 \lt k \lt 1\) it is exponential decay.

  30. anonymous
    • one year ago
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    oh thx

  31. mathstudent55
    • one year ago
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    Find f(8) and f(3). Then do (f(8) - f(3)) / (8 - 3)

  32. anonymous
    • one year ago
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    can u help me with these 2 For f(x) = 0.01(2)x, find the average rate of change from x = 3 to x = 8. 0.08 0.496 2.48 5 and A wrestling match has eliminations each round. The table below shows the number of wrestlers in each of the first 4 rounds of the tournament: Round (x) 1 2 3 4 Wrestlers f(x) 64 32 18 9 Compute the average rate of change of f(x) from x = 1 to x = 4 and identify the meaning of that rate. 55; there were 55 fewer wrestlers between rounds 1 and 4 3; there were 3 rounds between rounds 1 and 4 negative fifty five over three; on average, there were 55 fewer players for every 3 rounds negative three over fifty five; on average, there were 3 fewer players for every 55 rounds

  33. anonymous
    • one year ago
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    @mathstudent55

  34. anonymous
    • one year ago
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    @CBARREDO1

  35. mathstudent55
    • one year ago
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    Round x 1 4 Wrestlers f(x) 64 9 f(1) = 64 f(4) = 9 Subtract f(4) - f(1) and divided by the difference (4 - 1)

  36. anonymous
    • one year ago
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    So B?

  37. anonymous
    • one year ago
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    @mathstudent55 what about number 1

  38. anonymous
    • one year ago
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    55; there were 55 fewer wrestlers between rounds 1 and 4 3; there were 3 rounds between rounds 1 and 4 negative fifty five over three; on average, there were 55 fewer players for every 3 rounds negative three over fifty five; on average, there were 3 fewer players for every 55 rounds

  39. mathstudent55
    • one year ago
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    How did you get B? Read what I wrote above and do it. Then compare with the choices. Don't just guess.

  40. mathstudent55
    • one year ago
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    Round x 1 4 Wrestlers f(x) 64 9 f(1) = 64 f(4) = 9 Subtract f(4) - f(1) and divided by the difference (4 - 1) What is f(4) - f(1) = ?

  41. anonymous
    • one year ago
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    f(3)

  42. mathstudent55
    • one year ago
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    No. f(1) = 64 f(4) = 9 Use 64 and 9 for f(1) and f(4) What is f(4) - f(1) = ?

  43. anonymous
    • one year ago
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    -55 @mathstudent55

  44. anonymous
    • one year ago
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    @mathstudent55

  45. mathstudent55
    • one year ago
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    Correct. Now what is 4 - 1 ?

  46. anonymous
    • one year ago
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    3

  47. anonymous
    • one year ago
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    OHHHHHHHHH SO ITS C ON AVERAGE THERE WERE 55 FEWER PLAYERS FOR EVERY 3 ROUNDS

  48. anonymous
    • one year ago
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    @mathstudent55

  49. mathstudent55
    • one year ago
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    Correct.

  50. anonymous
    • one year ago
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    THANKS SO MUCH FOLLOW ME ON INSTAGRAM AT JHERRERA.29

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