Which of the following options is an equivalent function to f(x) = 3(2)3x?

- anonymous

Which of the following options is an equivalent function to f(x) = 3(2)3x?

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- anonymous

Answers:
f(x) = 3(8)x
f(x) = 24x
f(x) = 27(8)x
f(x) = 3(8x)

- anonymous

@Vocaloid

- DanJS

none

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## More answers

- anonymous

@DanJS what do u mean

- anonymous

@Vocaloid

- anonymous

@Saiyan @CBARREDO1 @Vocaloid please help

- anonymous

@Saiyan

- DanJS

As typed, you have
f(x) = 3 * 2 * 3*x = 18x
no way to get any of those answers with that...

- anonymous

@DanJS sry its 3(2)^3x

- CBARREDO1

f(x)= 3(8x)

- anonymous

|dw:1438038522974:dw|

- CBARREDO1

The answer is f(x)= 3(8x)

- anonymous

@DanJS

- CBARREDO1

THE ANSWER IS:
f(x)= 3(8x)

- anonymous

to the power of 3x

- anonymous

3(2)^3x

- CBARREDO1

@jaredhm29
THE ANSWER IS:
f(x)= 3(8x)

- anonymous

XD

- anonymous

it is A
\[ 3(8)^x\]

- CBARREDO1

What have I been saying?!

- anonymous

Which of the following options results in a graph that shows exponential decay?
f(x) = 0.6(2)x
f(x) = 3(0.7)x
f(x) = 0.4(1.6)x
f(x) = 20(3)x

- mathstudent55

\(f(x) = 3(2)^{3x}\)
Rule: To raise a power to a power, multiply powers.
\(\large (a^m)^n = a^{mn}\)
\(\large f(x) = 3(2)^{3x}\)
Apply the rule above in reverse to \(2^{3x} \)
\(\large f(x) = 3(2^3)^x\)
\(\large f(x) = 3 \cdot 8^x \)

- anonymous

Can u help Which of the following options results in a graph that shows exponential decay?
f(x) = 0.6(2)x
f(x) = 3(0.7)x
f(x) = 0.4(1.6)x
f(x) = 20(3)x @mathstudent55

- CBARREDO1

f(x) = 3(0.7)x

- anonymous

Which of the following options results in a graph that shows exponential growth?
f(x) = 0.4(3)x
f(x) = 3(0.5)x
f(x) = 0.8(0.9)x
f(x) = 0.9(5)−x

- CBARREDO1

f(x) = 0.4(3)x

- anonymous

For f(x) = 0.01(2)x, find the average rate of change from x = 3 to x = 8.
0.08
0.496
2.48
5

- anonymous

@CBARREDO1

- mathstudent55

\(\large f(x) = ak^x\)
As exponents become larger,
If \(k \gt 1\), it is exponential growth.
If \(0 \lt k \lt 1\) it is exponential decay.

- anonymous

oh thx

- mathstudent55

Find f(8) and f(3).
Then do (f(8) - f(3)) / (8 - 3)

- anonymous

can u help me with these 2
For f(x) = 0.01(2)x, find the average rate of change from x = 3 to x = 8.
0.08
0.496
2.48
5
and
A wrestling match has eliminations each round. The table below shows the number of wrestlers in each of the first 4 rounds of the tournament:
Round (x) 1 2 3 4
Wrestlers f(x) 64 32 18 9
Compute the average rate of change of f(x) from x = 1 to x = 4 and identify the meaning of that rate.
55; there were 55 fewer wrestlers between rounds 1 and 4
3; there were 3 rounds between rounds 1 and 4
negative fifty five over three; on average, there were 55 fewer players for every 3 rounds
negative three over fifty five; on average, there were 3 fewer players for every 55 rounds

- anonymous

@mathstudent55

- anonymous

@CBARREDO1

- mathstudent55

Round x 1 4
Wrestlers f(x) 64 9
f(1) = 64
f(4) = 9
Subtract f(4) - f(1) and divided by the difference (4 - 1)

- anonymous

So B?

- anonymous

@mathstudent55 what about number 1

- anonymous

55; there were 55 fewer wrestlers between rounds 1 and 4
3; there were 3 rounds between rounds 1 and 4
negative fifty five over three; on average, there were 55 fewer players for every 3 rounds
negative three over fifty five; on average, there were 3 fewer players for every 55 rounds

- mathstudent55

How did you get B?
Read what I wrote above and do it.
Then compare with the choices.
Don't just guess.

- mathstudent55

Round x 1 4
Wrestlers f(x) 64 9
f(1) = 64
f(4) = 9
Subtract f(4) - f(1) and divided by the difference (4 - 1)
What is f(4) - f(1) = ?

- anonymous

f(3)

- mathstudent55

No.
f(1) = 64
f(4) = 9
Use 64 and 9 for f(1) and f(4)
What is f(4) - f(1) = ?

- anonymous

-55 @mathstudent55

- anonymous

@mathstudent55

- mathstudent55

Correct.
Now what is 4 - 1 ?

- anonymous

3

- anonymous

OHHHHHHHHH SO ITS C ON AVERAGE THERE WERE 55 FEWER PLAYERS FOR EVERY 3 ROUNDS

- anonymous

@mathstudent55

- mathstudent55

Correct.

- anonymous

THANKS SO MUCH FOLLOW ME ON INSTAGRAM AT JHERRERA.29

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