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anonymous
 one year ago
Which of the following options is an equivalent function to f(x) = 3(2)3x?
anonymous
 one year ago
Which of the following options is an equivalent function to f(x) = 3(2)3x?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Answers: f(x) = 3(8)x f(x) = 24x f(x) = 27(8)x f(x) = 3(8x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@DanJS what do u mean

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Saiyan @CBARREDO1 @Vocaloid please help

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0As typed, you have f(x) = 3 * 2 * 3*x = 18x no way to get any of those answers with that...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@DanJS sry its 3(2)^3x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438038522974:dw

CBARREDO1
 one year ago
Best ResponseYou've already chosen the best response.1The answer is f(x)= 3(8x)

CBARREDO1
 one year ago
Best ResponseYou've already chosen the best response.1THE ANSWER IS: f(x)= 3(8x)

CBARREDO1
 one year ago
Best ResponseYou've already chosen the best response.1@jaredhm29 THE ANSWER IS: f(x)= 3(8x)

CBARREDO1
 one year ago
Best ResponseYou've already chosen the best response.1What have I been saying?!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Which of the following options results in a graph that shows exponential decay? f(x) = 0.6(2)x f(x) = 3(0.7)x f(x) = 0.4(1.6)x f(x) = 20(3)x

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0\(f(x) = 3(2)^{3x}\) Rule: To raise a power to a power, multiply powers. \(\large (a^m)^n = a^{mn}\) \(\large f(x) = 3(2)^{3x}\) Apply the rule above in reverse to \(2^{3x} \) \(\large f(x) = 3(2^3)^x\) \(\large f(x) = 3 \cdot 8^x \)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can u help Which of the following options results in a graph that shows exponential decay? f(x) = 0.6(2)x f(x) = 3(0.7)x f(x) = 0.4(1.6)x f(x) = 20(3)x @mathstudent55

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Which of the following options results in a graph that shows exponential growth? f(x) = 0.4(3)x f(x) = 3(0.5)x f(x) = 0.8(0.9)x f(x) = 0.9(5)−x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For f(x) = 0.01(2)x, find the average rate of change from x = 3 to x = 8. 0.08 0.496 2.48 5

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0\(\large f(x) = ak^x\) As exponents become larger, If \(k \gt 1\), it is exponential growth. If \(0 \lt k \lt 1\) it is exponential decay.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Find f(8) and f(3). Then do (f(8)  f(3)) / (8  3)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u help me with these 2 For f(x) = 0.01(2)x, find the average rate of change from x = 3 to x = 8. 0.08 0.496 2.48 5 and A wrestling match has eliminations each round. The table below shows the number of wrestlers in each of the first 4 rounds of the tournament: Round (x) 1 2 3 4 Wrestlers f(x) 64 32 18 9 Compute the average rate of change of f(x) from x = 1 to x = 4 and identify the meaning of that rate. 55; there were 55 fewer wrestlers between rounds 1 and 4 3; there were 3 rounds between rounds 1 and 4 negative fifty five over three; on average, there were 55 fewer players for every 3 rounds negative three over fifty five; on average, there were 3 fewer players for every 55 rounds

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Round x 1 4 Wrestlers f(x) 64 9 f(1) = 64 f(4) = 9 Subtract f(4)  f(1) and divided by the difference (4  1)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@mathstudent55 what about number 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.055; there were 55 fewer wrestlers between rounds 1 and 4 3; there were 3 rounds between rounds 1 and 4 negative fifty five over three; on average, there were 55 fewer players for every 3 rounds negative three over fifty five; on average, there were 3 fewer players for every 55 rounds

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0How did you get B? Read what I wrote above and do it. Then compare with the choices. Don't just guess.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Round x 1 4 Wrestlers f(x) 64 9 f(1) = 64 f(4) = 9 Subtract f(4)  f(1) and divided by the difference (4  1) What is f(4)  f(1) = ?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0No. f(1) = 64 f(4) = 9 Use 64 and 9 for f(1) and f(4) What is f(4)  f(1) = ?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Correct. Now what is 4  1 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OHHHHHHHHH SO ITS C ON AVERAGE THERE WERE 55 FEWER PLAYERS FOR EVERY 3 ROUNDS

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0THANKS SO MUCH FOLLOW ME ON INSTAGRAM AT JHERRERA.29
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