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Saiyan

  • one year ago

4. What is the simplest form of the expression. sqrt 3-sqrt 6/sqrt 3 + sqrt 6

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  1. Saiyan
    • one year ago
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    I would like some help because somewhere in the equation i am making a mistake in multiplying it by the conjugate.

  2. Nnesha
    • one year ago
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    show your work plz!

  3. Nnesha
    • one year ago
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    so we can find ur mistake :=)

  4. Nnesha
    • one year ago
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    what is the conjugate ?

  5. Saiyan
    • one year ago
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    |dw:1438037552571:dw|

  6. Nnesha
    • one year ago
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    right now multiply \[\huge\rm \frac{ (\sqrt{3} - \sqrt{6})(\sqrt{3} - \sqrt{6}) }{ (\sqrt{3}+ \sqrt{6}) (\sqrt{3}-\sqrt{6}) }\] now apply foil method at the top and bottom

  7. anonymous
    • one year ago
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    @Nnesha after you are done helping him, can you please help me

  8. Saiyan
    • one year ago
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    \[\sqrt{3}^2-\sqrt{6}^2/(\sqrt{3}-\sqrt{6})^2\]

  9. Nnesha
    • one year ago
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    well parentheses at the numerator are the same but not at the denominator careful abt signs

  10. Nnesha
    • one year ago
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    \[\huge\rm \frac{ (\sqrt{3} \color{reD}{-} \sqrt{6})(\sqrt{3} \color{REd}{-} \sqrt{6}) }{ (\sqrt{3}\color{Red}{+} \sqrt{6}) (\sqrt{3}\color{Red}{-}\sqrt{6}) }\] familiar wit the foil method ?

  11. Saiyan
    • one year ago
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    yes

  12. Nnesha
    • one year ago
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    good so apply that :=)

  13. Saiyan
    • one year ago
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    the answer i typed above was my answer to that

  14. Nnesha
    • one year ago
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    is it 3^2 under the square root ?

  15. Saiyan
    • one year ago
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    no

  16. Nnesha
    • one year ago
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    \[(\sqrt{3})^2\] like this ?

  17. Saiyan
    • one year ago
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    yes

  18. Nnesha
    • one year ago
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    well no that's right

  19. Nnesha
    • one year ago
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    |dw:1438038779860:dw| try again \[\huge\rm \color{ReD}{\sqrt{3}}({\sqrt{3}} -\sqrt{6}) \color{ReD}{- \sqrt{6}}(\sqrt{3}- \sqrt{6})\] distribute

  20. Saiyan
    • one year ago
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    ok hold on

  21. Saiyan
    • one year ago
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    \[\sqrt{9}-\sqrt{18}-\sqrt{18}+\sqrt{36}\]

  22. Nnesha
    • one year ago
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    perfect take square rot of 9 and 36 combine - s quare root of 18

  23. Saiyan
    • one year ago
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    3+6-sqrt36

  24. Nnesha
    • one year ago
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    what is square root of 36 ?

  25. Nnesha
    • one year ago
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    \[\sqrt{9}\color{Red}{-\sqrt{18}-\sqrt{18}}+\sqrt{36}\] combine those two terms

  26. Saiyan
    • one year ago
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    3-sqrt36+6

  27. Nnesha
    • one year ago
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    \[\sqrt{9}\color{Red}{-\sqrt{18}-\sqrt{18}}+\sqrt{36}\] \[3 ~~\color{REd}{??????} +6\] square root of 36 is 6 and now -sqr{18} - sqt{18} isn't equal to sqrt{36

  28. Nnesha
    • one year ago
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    it is same as x^2 + x^2 = 2x^2

  29. Saiyan
    • one year ago
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    -18-18=36

  30. Saiyan
    • one year ago
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    -36

  31. Nnesha
    • one year ago
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    nope it's not just -18 let's say \[\sqrt{18}=x^2\] so -x^2 -x^2 =what ?

  32. Saiyan
    • one year ago
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    -2x^2

  33. Nnesha
    • one year ago
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    yes right now change x^2 with sqrt{18) so u get ?

  34. Saiyan
    • one year ago
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    18

  35. Nnesha
    • one year ago
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    we assume that sqrt{18} is x^2 so just replace x^2 by sqrt{18} you will get \[-2\sqrt{18}\]

  36. Nnesha
    • one year ago
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    you need to combine them not multiply

  37. Nnesha
    • one year ago
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    add

  38. Nnesha
    • one year ago
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    just like x+x = 2x same way \[-\sqrt{18}-\sqrt{18} = -2\sqrt{18}\]

  39. Saiyan
    • one year ago
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    oh ok

  40. Nnesha
    • one year ago
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    yes so numerator is \[\frac{ \color{Red}{3}-2\sqrt{18}+\color{Red}{6} }{ }\] combine like terms

  41. Nnesha
    • one year ago
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    and then apply foil method at the denominator \[(\sqrt{3}+\sqrt{6})(\sqrt{3}-\sqrt{6}) = ?\]

  42. Saiyan
    • one year ago
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    so it 9-2 to the sqrt 18

  43. Nnesha
    • one year ago
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    yep right and then you have to factor sqrt 18

  44. Saiyan
    • one year ago
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    ok i got the answer thx

  45. Nnesha
    • one year ago
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    u sure ?

  46. Saiyan
    • one year ago
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    yep now i understand

  47. Saiyan
    • one year ago
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    thx

  48. Nnesha
    • one year ago
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    alright then . let me know if u need help my pleasure :=)

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