Solving Systems of Equations by Substitution. 1. -3x + 3y = 4 -x + y = 3 2. -5x - 8y = 17 2x - 7y = -17

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Solving Systems of Equations by Substitution. 1. -3x + 3y = 4 -x + y = 3 2. -5x - 8y = 17 2x - 7y = -17

Mathematics
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This is my work for question 1. we could figure out the value of y by: y = 3 + x -3x + 3(3 + x) = 4 is that correct?

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i need to solve for x, which i know, but i just wanted to know whether my set up was fine or not.
yep yep right :=)
so then we can simply it to: -3x + 9 + 3x = 4
yep
but if we do -3x + 3x = 0x and I am not even sure if there is any such thing as 0x.
yes so they cancel out
thats mean no solution both sides are not equal \[9 \cancel =4\]
oh okay :)
and for the next one...
yep
we can figure out the value of x... 2x - 7y = -17 2x = -17 + 7y 2x / 2 = (-17 + 7x) / 2 x = -8.5 + 3.5x
hmm you mean x = -8.5 +3.5 y right ?
yes sorry :)
its okay yep right
-5(-8.5 + 3.5y) - 8y = 17
42.5 - 17.5y - 8y = 17 42.5 - 25.5y = 17 -25.5 - 25.5y = 17 -25.5y = 42.5 y = 1.67 i am pretty sure i am wrong it's going on decimals.
well i don't understand the 3rd line
if i did 17 - 42.5 = -25.5
yep that's right you need to move 42.5 to the right side then you will get Perfect one
what do you mean by moving 42.5?
i meant you have to subtract 42.5 both sides :=)
correct
so what i did was correct right?
\(\color{blue}{\text{Originally Posted by}}\) @calculusxy 42.5 - 17.5y - 8y = 17 42.5 - 25.5y = 17 -25.5 - 25.5y = 17 -25.5y = 42.5 y = 1.67 i am pretty sure i am wrong it's going on decimals. \(\color{blue}{\text{End of Quote}}\) well here 3rd line you need to subtract 42.5 both sides i don't why there is -25.5 -25.5y
oh yeah
my mistake :\
:=) doing gREAT
y = 1 right?
yep right!
and then we would do: -5x - 8(1) = 17 -5x - 8 = 17 -5x = 25 x = -5
gO_OD to go!
thanks :) I have another question. it's small and related to basic physics. can u help?
PHYSICS hmmmm not sure
can u just see it? if u can't do it then u don't have to.
ye sure!
okay. here it is...
If i'm driving in a car at 30kph and a friend is driving in a car with the same mass at 60kph, my friend's car's kinetic energy is bigger than mine by a factor of what? (that is, divide my friend's over mine.)
i'm not sure havn't done physics n a while sorry
okay thank you though :)
np good job!

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