Where is the orthocenter of obtuse triangle CDE located? Find GD. A.outside of the triangle; GD = 5 B.inside the triangle; GD = 5 C.outside of the triangle; GD = 7 D.inside the triangle; GD = 7

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Where is the orthocenter of obtuse triangle CDE located? Find GD. A.outside of the triangle; GD = 5 B.inside the triangle; GD = 5 C.outside of the triangle; GD = 7 D.inside the triangle; GD = 7

Mathematics
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Is there a figure?
We know that EGC is the supplementary angle of CGD, so: ∠EGC=180∘−∠CGD=180∘90∘=90∘ But we are also told that: EGC=(5x+55)∘ So we can say: (5x+55)∘=90∘5x+55=905x=90−55=35x=355=7 So: GD=2x−9=2⋅7−9=14−9=5
Also, for obtuse triangles the orthocenter will be outside the triangle: http://www.mathopenref.com/triangleorthocenter.html

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Other answers:

|dw:1438041362735:dw|
almost but still good
|dw:1438041511499:dw|
yep
so it would be B?
|dw:1438042558002:dw|
5x + 55 = 90 5x = 35 x = 7 |dw:1438042639067:dw|
GD = 2x - 9 GD = 2(7) - 9 GD = 14 - 9 GD = 5 |dw:1438042673723:dw|
so it would be A? because you solved outside the triangle ? @mathstudent55
Yes. The orthocenter is outside the triangle and GD = 5. A is the answer.
Thank you !!
You're welcome.

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