Photon336
  • Photon336
Question
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Photon336
  • Photon336
Questions below
1 Attachment
Photon336
  • Photon336
@Rushwr
taramgrant0543664
  • taramgrant0543664
Wouldn't it be A? Products over reactants, stoiciometric coefficients become powers

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

taramgrant0543664
  • taramgrant0543664
For the second one if you removes CH4 then the reaction would want to go to the left. Adding CO would drive the reaction left as well. Removing H2 would cause the reaction to be driven right causing H2 to be produced
taramgrant0543664
  • taramgrant0543664
As for pressure I couldn't remember what principle it was but its Le Chatelier's Principle and pressure will Try to even out the number of moles the right side has 4 and the left side has 2 so increasing the pressure would drive the reaction left so B is the answer for the second one
Rushwr
  • Rushwr
For the 1st question it is A For the 2nd question it is B. A is wrong cuz if we add CO the system will produce more CH4 and H2O in order to regain its equilibrium. B is correct cuz when we remove H2 the system is lacking H2 and it effects te equilibrium hence it tends to form more H2. C is wrong , if we remove CH4 that is we are removing a reactant . In order to regain its eqm. CH4 is formed favoring the reverse reaction. D is wrong . U see that the total moles in the product side is 4 while the total moles in the reactant side is 2 hence if we increase the pressure the equilibrium will shift to left side again.
Photon336
  • Photon336
\[NO _{2}(g) + O _{2}(g) \rightarrow 2NO _{2}(g)\]
Photon336
  • Photon336
\[\frac{ [NO2]^{2} }{ [NO]^{2} [O2] } = K _{eq}\]
Photon336
  • Photon336
We only consider gases in the equilibrium expression, rather than solids and pure liquids because the concentration of solids, & pure liquids doesn't change much.
Photon336
  • Photon336
the first one is A
Photon336
  • Photon336
2 is B
Photon336
  • Photon336
removing \[H _{2}\] from the reaction will cause it to go to the right.
Photon336
  • Photon336
will post another!

Looking for something else?

Not the answer you are looking for? Search for more explanations.