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anonymous
 one year ago
PLEASE CAN SOMEONE HELP ME WITH 2 TRIG QUESTIONS THAT I HAVE BEEN STUCK ON FOR ABOUT 2 DAYS AND NOBODY SEEMS TO HELP ME!
anonymous
 one year ago
PLEASE CAN SOMEONE HELP ME WITH 2 TRIG QUESTIONS THAT I HAVE BEEN STUCK ON FOR ABOUT 2 DAYS AND NOBODY SEEMS TO HELP ME!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0work backwards, determine your amp, period , phase shift, vertical/ horizontal shift

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can someone just show me how to solve the first one so that I can do the second one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hey isn't that from con nexus

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no its from my trig class in Texas

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u help me or not?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if that problem is really from where you say it is, can you give me a link so I cam find a solution

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha you helped me before on these problems, can u help me one last time

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh im not looking to graph, im just trying to find a function out of a graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Please help @Vocaloid

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2#3 has an asymptote, and its range is the set of all real numbers, so the function is either tan or cot

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2let's assume it's tan(x) what is the value of tan(x) when x = pi/4

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2so IF the point (pi/4, 1) was on the graph, then tan(x) might be the answer. But it's not

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2something like 4*tan(x) would work but if we plugged in x = pi/2, then we'd get undefined. The function f(x) = tan(x) is undefined when x = pi/2. So it turns out that tan doesn't even work at all

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2is this making sense?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i see, so it has to be cotangent

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2what is the value of cot(x) when x = pi/4 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the answer is 1, but if I put a 4 behind cotangent: 4cot(pi/4) then it is 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and it works with the rest as well

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2so it appears that 4*cot(x) works. Check the other x coordinates to see if it holds up for the other two points

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2yes 4*cot(x) = 0 when x = pi/2 and 4*cot(x) = 4 when x = 3pi/4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so is thar it then, the function for this graphy is just y=4cot(x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is that how you properly write it down:\[y=4\cot (x)\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2or f(x) = 4*cot(x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how about the second one, that is the really confusing one

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2what's the vertical distance from the very peak of one mountain to the very bottom of the valley? dw:1438045445818:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2hint: look at the points (pi/6, 10) and (5pi/6, 10) specifically the y coordinates

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok i looked at them, just a question when you asked me the distance from the peak of the mountain to the bottom, did you already know the answer or were you asking me because the graph was unclear?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2I knew the answer. I wanted to get you thinking on how to solve this problem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry im stuck and i dont know where you were going with in the hint

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2what is the change from y = 10 to y = 10

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2cut that in half to get 20/2 = 10 the amplitude is 10 units. This is the distance from the center to the peak

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2look at the graph and tell me what the two peak points are

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2how are you getting them? look at the attachment. They give you the points

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0arent they the two highest points

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2they list the points below the graph

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.22 of them are peak points

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2yeah they are the highest points

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(4\pi/3,0) and (11\pi/6,10)\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2there's a point higher than (4pi/3, 0)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2(11pi/6, 10) is one of the peak points

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2yes, now subtract the x coordinates

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2(11pi/6)  (pi/6) = ???

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2so that is the period. Every 2pi units, the function repeats itself

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2let's assume this is a cosine function when x = 0, cos(x) = 1 and 10*cos(x) = 10 however, the point (0,10) isn't on this function. Instead, it's shifted to the left pi/6 units. So we need to account for the phase shift phase shift = pi/6 the negative tells us to go left

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are we sure its a cosine function, could it not be something else

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2either that or sine

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2cosine is easier to work with though

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2A = amplitude = 10 T = period = 2pi P = phase shift = pi/6  The general cosine equation is y = A*cos(Bx  C) + D where A is the amplitude T = 2pi/B is the period C/B is the phase shift y = D is the midline. In this case, the midline is y = 0 so D = 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im confused as to how to write the equation out

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2If T = 2pi/B is the period and we know T = 2pi is the period, then what is the value of B?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2A = 10 B = 1 C = unknown to find C, solve C/B = pi/6

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2yes, so the function is \[\Large f(x) = 10\cos\left(x + \frac{\pi}{6}\right)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0uhhhh, Im graphing this equation, but it looks nothing like the graph given

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2what are you using to graph?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2you mean this? https://www.desmos.com/calculator

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2and you typed in 10*cos(x+pi/6) ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2are you in radian mode?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2this is what I get

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh wait it is working now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if its not a problem can I ask you a way simpler question, that will only take 5 minutes

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how to we graph this function: \[y=3\sec(\pi2x)+5\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2by using \[\Large \sec(x) = \frac{1}{\cos(x)}\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2or desmos should be able to handle secant functions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah, but i'm not getting a proper graph, im just getting something like this:

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2that's what secant graphs look like. They have asymptotes and those U shapes
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