Hillary jogged a total distance of 7 and 1 over 3miles during the months of October and November. If Hillary only jogged 1 over 6mile every day, which expression shows the number of days she went jogging?
7 and 1 over 3 multiplied by 1 over 6 7 and 1 over 3 plus 1 over 6 7 and 1 over 3 minus 1 over 6 7 and 1 over 3 divided by 1 over 6

- anonymous

- jamiebookeater

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- anonymous

- anonymous

- anonymous

anyone help plz

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## More answers

- anonymous

- jim_thompson5910

Divide the total distance by the number of miles jogged per day.

- anonymous

so whats the answer

- anonymous

how do u get it

- anonymous

i have trouble with fractions

- anonymous

- jim_thompson5910

It might help to convert 7 & 1/3 into an improper fraction. Do you know how to do that?

- anonymous

a little :(

- jim_thompson5910

multiply the denominator 3 with the whole part 7 to get 21
then add on the numerator: 21+1 = 22
so \[\Large 7 \frac{1}{3} = \frac{22}{3}\]
make sense?

- anonymous

ya

- jim_thompson5910

now divide 22/3 over 1/6

- jim_thompson5910

that is the same as saying 22/3 times 6/1

- anonymous

ssooo what do i have to do now

- jim_thompson5910

multiply 22/3 times 6/1

- anonymous

44

- jim_thompson5910

multiply straight across like last time

- jim_thompson5910

44 is correct

- anonymous

yes!

- jim_thompson5910

she went jogging for 44 days

- anonymous

so what is the answer these r the choices
7 and 1 over 3 multiplied by 1 over 6 7 and 1 over 3 plus 1 over 6 7 and 1 over 3 minus 1 over 6 7 and 1 over 3 divided by 1 over 6

- jim_thompson5910

well like I said above: Divide the total distance by the number of miles jogged per day.

- jim_thompson5910

\[\Large \text{Answer} = \frac{\text{Total Distance}}{\text{Miles jogged per day}}\]

- anonymous

ohhhh

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