At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

It can be written as the power of a power:
\[\large \sqrt[5]{(-3)^{5}}=((-3)^{5})^\frac{1}{5}\]

Just multiply the indices (5 * (1/5).

HI!!

the fifth root of whatever to the power of five is whatever

\[\huge \sqrt[5]{\diamondsuit^5}=\diamondsuit\]

@misty1212 Do you think you could help me with another problem?

sure

and yes, it is the same number that is inside, so your answer should be \(-3\)

Cool, um, my next question is a 5th root of -1/32

your job is to think of a number that, when raised to the fifth power, is 32

if you do not get it, let me know
if you do, say it

So it'd just be multiplying something by itself to get to 32?

yes one number, multiplied by itself five times, to give 32

i will be happy to tell you if you like

Would it be 2? and since it's a negative 32, the answer would be -2?

yes \(2^5=32\) so \(\sqrt[5]{32}=2\) but as i said, we are still not done

you want
\[\sqrt{-\frac{1}{32}}\] which is the same as
\[\frac{\sqrt[5] 1}{\sqrt[5]{-32}}\]

\[\sqrt[5]{1}=1\] and
\[\sqrt[5]{-32}=-2\]

So would it be the 5th root 1 over -2?

no it would just be
\[-\frac{1}{2}\]

not the fifth root, you already took the fifth root

Ohhh, I see now.

ok good !!

Thank you! :)

\[\huge \color\magenta\heartsuit\]