anonymous
  • anonymous
5th root (-3)^5 ._.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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kropot72
  • kropot72
It can be written as the power of a power: \[\large \sqrt[5]{(-3)^{5}}=((-3)^{5})^\frac{1}{5}\]
kropot72
  • kropot72
Just multiply the indices (5 * (1/5).
misty1212
  • misty1212
HI!!

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misty1212
  • misty1212
the fifth root of whatever to the power of five is whatever
misty1212
  • misty1212
\[\huge \sqrt[5]{\diamondsuit^5}=\diamondsuit\]
anonymous
  • anonymous
So if it's the same number it's going to be whatever the inside number is? (I have no clue if that made sense)
anonymous
  • anonymous
@misty1212 Do you think you could help me with another problem?
misty1212
  • misty1212
sure
misty1212
  • misty1212
and yes, it is the same number that is inside, so your answer should be \(-3\)
anonymous
  • anonymous
Cool, um, my next question is a 5th root of -1/32
anonymous
  • anonymous
I don't understand fractions all that well and since I'm new to this whole 5th root, I'm extremely confused about it.
misty1212
  • misty1212
your job is to think of a number that, when raised to the fifth power, is 32
misty1212
  • misty1212
don't think too hard , it is easy to come by that is not the final answer btw, but that is the first step
misty1212
  • misty1212
if you do not get it, let me know if you do, say it
anonymous
  • anonymous
So it'd just be multiplying something by itself to get to 32?
misty1212
  • misty1212
yes one number, multiplied by itself five times, to give 32
misty1212
  • misty1212
i will be happy to tell you if you like
anonymous
  • anonymous
Would it be 2? and since it's a negative 32, the answer would be -2?
misty1212
  • misty1212
yes \(2^5=32\) so \(\sqrt[5]{32}=2\) but as i said, we are still not done
misty1212
  • misty1212
you want \[\sqrt{-\frac{1}{32}}\] which is the same as \[\frac{\sqrt[5] 1}{\sqrt[5]{-32}}\]
misty1212
  • misty1212
\[\sqrt[5]{1}=1\] and \[\sqrt[5]{-32}=-2\]
anonymous
  • anonymous
So would it be the 5th root 1 over -2?
misty1212
  • misty1212
no it would just be \[-\frac{1}{2}\]
misty1212
  • misty1212
not the fifth root, you already took the fifth root
anonymous
  • anonymous
Ohhh, I see now.
misty1212
  • misty1212
ok good !!
anonymous
  • anonymous
Thank you! :)
misty1212
  • misty1212
\[\huge \color\magenta\heartsuit\]

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