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lokiando
 one year ago
pls help!
Faelyn grouped the terms and factored the GCF out of the groups of the polynomial 6x4 – 8x2 + 3x2 + 4. Her work is shown.
Step 1: (6x^4 – 8x^2) + (3x^2 + 4)
Step 2: 2x^2(3x^2 – 4) + 1(3x^2 + 4)
Faelyn noticed that she does not have a common factor. Which accurately describes what Faelyn should do next?
lokiando
 one year ago
pls help! Faelyn grouped the terms and factored the GCF out of the groups of the polynomial 6x4 – 8x2 + 3x2 + 4. Her work is shown. Step 1: (6x^4 – 8x^2) + (3x^2 + 4) Step 2: 2x^2(3x^2 – 4) + 1(3x^2 + 4) Faelyn noticed that she does not have a common factor. Which accurately describes what Faelyn should do next?

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.2is this \[6x^48x^2+3x^2+4\]?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2it is the same as \[6x^45x^2+4\] when you combine like terms

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2but it does not factor, so the question "what should Faelyn do next" has not real answer other than "go have a beer"

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2not sure what the options are looks like you were given choices

lokiando
 one year ago
Best ResponseYou've already chosen the best response.0a) Faelyn should realize that her work shows that the polynomial is prime. b) Faelyn should go back and regroup the terms in Step 1 as (6x^4 + 3x^2) – (8x^2 + 4). c) In Step 2, Faelyn should factor only 2x out of the first expression. d) Faelyn should factor out a negative from one of the groups so the binomials will be the same

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2hmm not really clear probably the first one, because it is prime but that is not a proof that it is prime we can check the other ones

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2b) Faelyn should go back and regroup the terms in Step 1 as (6x^4 + 3x^2) – (8x^2 + 4). this does not help

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2c) In Step 2, Faelyn should factor only 2x out of the first expression. this does not help either

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2d) Faelyn should factor out a negative from one of the groups so the binomials will be the same this is wrong as well, not really clear it is prime, so no matter what you do you will not be able to factor it

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2it still does not factor

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2no matter what you do might as well throw in the towel

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0actually we can combine like terms for the x^2 part making the equation \[6x^45x^2+4\] now we can factor if and only if we have a perfect square result from the discriminant formula which is \[b^24ac\] so letting b = 5,a = 6, and c = 4 \[(5)^24(6)(4)\] \[2596 = 71\] not a perfect square so this quadratic equation can't be factored. The quadratic formula needs to be used, but it's not asking to solve further in this question. So, this is a prime polynomial because in the discriminant we had 71. the number 71 is indeed a prime number. However, taking the square root of 71 we have \[\sqrt{71}i\]. since negative numbers aren't allowed in the radical the result is imaginary or i. all the roots for this equation is complex.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0sorry only saw earlier post when the equation wasn't combined for the first line of my comment
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