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What do you think the answer is?
I already have the answer. It would ruin it.
|dw:1438054391038:dw| think obtuse
Wouldn't you use the law of cosines to get one angle, then use the law of sines?
so your answer is obtuse.
yes because one angle is more than 90 but I don't see a triangle with those measurements
I know the answer - it is acute
can you really make a triangle with those measurements?
Why would it be acute wolf?
I used an online triangle calculator Still, I'm sure your instructor would want it worked out right?
The answer is acute.
You got it right.
Okay - they just don't want people to give out answers directly. Do you want it worked out?
No, its fine.
Okay then :-)
can you get a triangle with those measurements?
Let's use the Law of Cosines cos (A) = (b^2 + c^2 -a^2) / (2*b*c) cos (A) = (34^2 + 42^2 -28^2) / (2*34*42) cos (A) = 2,136 / 2,856 cos (A) = 0.7478991597 Angle A = 41.591 Degrees For the second angle, let's use the Law of Sines sin (B) = (b • sin(A)) / a sin (B) = (34 * sin (41.591))/a sin (B) = (34 * 0.66381)/28 sin (B) = 0.806055 Angle B = 53.712 Angle C = 180 -41.591 -53.712 Angle C = 84.697 All 3 angles are less than 90 degrees and therefore it is a right triangle.
@wolf1728 thank you error on the last line not right triangle acute triangle I was told to always find the largest angle first seems like it does not really matter My concern was the lengths isn't there some rule about the possible lengths of the 3rd side given 2 lengths? but my 2 mistakes 1) since the factor would make the requirement 35 and we only had 34 should know acute 2) name the triangle by the angles since one angle was obtuse the triangle obtuse
Geez, I did all that work and TYPED the wrong answer!! All angle less than 90 degrees so it is an ACUTE triangle.