anonymous
  • anonymous
Please help! Picture attached Let logbA=3; logbC=2; logbD=5 What is the value of logb(A^3D^4)/c^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
1 Attachment
UsukiDoll
  • UsukiDoll
I think this will be a bit easier if we use log rules to expand this equation and then use the values given to get the result
UsukiDoll
  • UsukiDoll
all three log rules are being used here.. use the first and second one

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More answers

UsukiDoll
  • UsukiDoll
|dw:1438056585533:dw|
UsukiDoll
  • UsukiDoll
|dw:1438056623746:dw|
UsukiDoll
  • UsukiDoll
|dw:1438056660052:dw|
UsukiDoll
  • UsukiDoll
so use those log rules and expand |dw:1438056709210:dw|
anonymous
  • anonymous
is it 3logbA+4logbD - 2logbC
UsukiDoll
  • UsukiDoll
don't give the direct answer @CBARREDO1
UsukiDoll
  • UsukiDoll
giving direct answers is against code of conduct. delete that.
UsukiDoll
  • UsukiDoll
no you're not.. you just gave a direct answer and interrupted me.
UsukiDoll
  • UsukiDoll
ugh I hate being interrupted. -_-
UsukiDoll
  • UsukiDoll
@.Sam.
anonymous
  • anonymous
I got c. 25 after 3(3)+4(5)-2(2)
UsukiDoll
  • UsukiDoll
giving direct answers is against code of conduct. @.Sam. can you do something about this? I got interrupted real bad here
UsukiDoll
  • UsukiDoll
I don't appreciate being interrupted by someone who just gives direct answers.
CBARREDO1
  • CBARREDO1
After reading your explanation i tried to get the answer and I got it right, Whats wrong with that?
UsukiDoll
  • UsukiDoll
you gave a direct answer you interrupted me that's the problem.
CBARREDO1
  • CBARREDO1
I went ahead and guessed from your explanations
UsukiDoll
  • UsukiDoll
stop replying man... it's not worth it.
UsukiDoll
  • UsukiDoll
You're not the original asker. I'm guiding the original asker to the problem and you went in here and gave a direct answer, interrupted me, and being disrespectful.
UsukiDoll
  • UsukiDoll
@mishtea are you there? let's see if you got the attempt right.. (I'll double check) sorry about that. I hate it when rude users come and give direct answers thinking that they will get away with it.
UsukiDoll
  • UsukiDoll
so your attempt was "is it 3logbA+4logbD - 2logbC"
UsukiDoll
  • UsukiDoll
|dw:1438057280167:dw|
anonymous
  • anonymous
haha its ok! and yes then i substitute it for 3(3)+4(5)-2(2)
UsukiDoll
  • UsukiDoll
|dw:1438057287255:dw| alright I'm getting there XD sorry I have high blood pressure from that guy
UsukiDoll
  • UsukiDoll
|dw:1438057350273:dw|
UsukiDoll
  • UsukiDoll
lol wrong letter but the process is correct
UsukiDoll
  • UsukiDoll
|dw:1438057401521:dw| so given that \[\log_{b}A = 3, \log_{b}C =2, \log_{b}D = 5\]
UsukiDoll
  • UsukiDoll
|dw:1438057462601:dw| I got 25 too.. so we've done this correctly.
UsukiDoll
  • UsukiDoll
lol that guy got it way off XD good thing we didn't listen to him
anonymous
  • anonymous
yay, thank you!!! :)
UsukiDoll
  • UsukiDoll
his answer wasn't even in the choices lawlz

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