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anonymous

  • one year ago

Please help! Picture attached Let logbA=3; logbC=2; logbD=5 What is the value of logb(A^3D^4)/c^2

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  1. anonymous
    • one year ago
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  2. UsukiDoll
    • one year ago
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    I think this will be a bit easier if we use log rules to expand this equation and then use the values given to get the result

  3. UsukiDoll
    • one year ago
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    all three log rules are being used here.. use the first and second one

  4. UsukiDoll
    • one year ago
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    |dw:1438056585533:dw|

  5. UsukiDoll
    • one year ago
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    |dw:1438056623746:dw|

  6. UsukiDoll
    • one year ago
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    |dw:1438056660052:dw|

  7. UsukiDoll
    • one year ago
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    so use those log rules and expand |dw:1438056709210:dw|

  8. anonymous
    • one year ago
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    is it 3logbA+4logbD - 2logbC

  9. UsukiDoll
    • one year ago
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    don't give the direct answer @CBARREDO1

  10. UsukiDoll
    • one year ago
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    giving direct answers is against code of conduct. delete that.

  11. UsukiDoll
    • one year ago
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    no you're not.. you just gave a direct answer and interrupted me.

  12. UsukiDoll
    • one year ago
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    ugh I hate being interrupted. -_-

  13. UsukiDoll
    • one year ago
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    @.Sam.

  14. anonymous
    • one year ago
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    I got c. 25 after 3(3)+4(5)-2(2)

  15. UsukiDoll
    • one year ago
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    giving direct answers is against code of conduct. @.Sam. can you do something about this? I got interrupted real bad here

  16. UsukiDoll
    • one year ago
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    I don't appreciate being interrupted by someone who just gives direct answers.

  17. CBARREDO1
    • one year ago
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    After reading your explanation i tried to get the answer and I got it right, Whats wrong with that?

  18. UsukiDoll
    • one year ago
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    you gave a direct answer you interrupted me that's the problem.

  19. CBARREDO1
    • one year ago
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    I went ahead and guessed from your explanations

  20. UsukiDoll
    • one year ago
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    stop replying man... it's not worth it.

  21. UsukiDoll
    • one year ago
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    You're not the original asker. I'm guiding the original asker to the problem and you went in here and gave a direct answer, interrupted me, and being disrespectful.

  22. UsukiDoll
    • one year ago
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    @mishtea are you there? let's see if you got the attempt right.. (I'll double check) sorry about that. I hate it when rude users come and give direct answers thinking that they will get away with it.

  23. UsukiDoll
    • one year ago
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    so your attempt was "is it 3logbA+4logbD - 2logbC"

  24. UsukiDoll
    • one year ago
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    |dw:1438057280167:dw|

  25. anonymous
    • one year ago
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    haha its ok! and yes then i substitute it for 3(3)+4(5)-2(2)

  26. UsukiDoll
    • one year ago
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    |dw:1438057287255:dw| alright I'm getting there XD sorry I have high blood pressure from that guy

  27. UsukiDoll
    • one year ago
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    |dw:1438057350273:dw|

  28. UsukiDoll
    • one year ago
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    lol wrong letter but the process is correct

  29. UsukiDoll
    • one year ago
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    |dw:1438057401521:dw| so given that \[\log_{b}A = 3, \log_{b}C =2, \log_{b}D = 5\]

  30. UsukiDoll
    • one year ago
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    |dw:1438057462601:dw| I got 25 too.. so we've done this correctly.

  31. UsukiDoll
    • one year ago
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    lol that guy got it way off XD good thing we didn't listen to him

  32. anonymous
    • one year ago
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    yay, thank you!!! :)

  33. UsukiDoll
    • one year ago
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    his answer wasn't even in the choices lawlz

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