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anonymous

  • one year ago

What is the electric field on the surface of a thin conducting spherical shell containing uniform charge Q?

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  1. anonymous
    • one year ago
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    Is it kQ/r^2 or 0?

  2. anonymous
    • one year ago
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    @dan815

  3. Rushwr
    • one year ago
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    \[E=\frac{ 1 }{ 4\pi \epsilon } \frac{ Q }{R ^{2}}\]

  4. anonymous
    • one year ago
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    How to derive that?

  5. IrishBoy123
    • one year ago
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    use a Gausssian surface and Gauss's Law [\(\Phi = \int \vec E . \hat n \ da = \frac{ Q_{enc}}{\epsilon_o} \)]. if the outer radius of the shell is R, then \(\large E \times 4 \pi R^2 = \frac{Q}{\epsilon_o}\) -- leading to the formula posted above you can generalise for all radii

  6. anonymous
    • one year ago
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    I understand the electric fields inside and outside the shell, but I'm having doubt only about a point on the shell, since it's a thin shell is charge Q enclosed within the Gaussian surface?

  7. IrishBoy123
    • one year ago
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    doesn't really matter if its thin or thick; as long as it's conducting, the charge will be at the surface so looks to me like a practical question.

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