A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
What is the electric field on the surface of a thin conducting spherical shell containing uniform charge Q?
anonymous
 one year ago
What is the electric field on the surface of a thin conducting spherical shell containing uniform charge Q?

This Question is Open

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.0\[E=\frac{ 1 }{ 4\pi \epsilon } \frac{ Q }{R ^{2}}\]

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1use a Gausssian surface and Gauss's Law [\(\Phi = \int \vec E . \hat n \ da = \frac{ Q_{enc}}{\epsilon_o} \)]. if the outer radius of the shell is R, then \(\large E \times 4 \pi R^2 = \frac{Q}{\epsilon_o}\)  leading to the formula posted above you can generalise for all radii

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I understand the electric fields inside and outside the shell, but I'm having doubt only about a point on the shell, since it's a thin shell is charge Q enclosed within the Gaussian surface?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1doesn't really matter if its thin or thick; as long as it's conducting, the charge will be at the surface so looks to me like a practical question.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.