## anonymous one year ago What is the electric field on the surface of a thin conducting spherical shell containing uniform charge Q?

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1. anonymous

Is it kQ/r^2 or 0?

2. anonymous

@dan815

3. Rushwr

$E=\frac{ 1 }{ 4\pi \epsilon } \frac{ Q }{R ^{2}}$

4. anonymous

How to derive that?

5. IrishBoy123

use a Gausssian surface and Gauss's Law [$$\Phi = \int \vec E . \hat n \ da = \frac{ Q_{enc}}{\epsilon_o}$$]. if the outer radius of the shell is R, then $$\large E \times 4 \pi R^2 = \frac{Q}{\epsilon_o}$$ -- leading to the formula posted above you can generalise for all radii

6. anonymous

I understand the electric fields inside and outside the shell, but I'm having doubt only about a point on the shell, since it's a thin shell is charge Q enclosed within the Gaussian surface?

7. IrishBoy123

doesn't really matter if its thin or thick; as long as it's conducting, the charge will be at the surface so looks to me like a practical question.