anonymous
  • anonymous
What is the electric field on the surface of a thin conducting spherical shell containing uniform charge Q?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Is it kQ/r^2 or 0?
anonymous
  • anonymous
@dan815
Rushwr
  • Rushwr
\[E=\frac{ 1 }{ 4\pi \epsilon } \frac{ Q }{R ^{2}}\]

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anonymous
  • anonymous
How to derive that?
IrishBoy123
  • IrishBoy123
use a Gausssian surface and Gauss's Law [\(\Phi = \int \vec E . \hat n \ da = \frac{ Q_{enc}}{\epsilon_o} \)]. if the outer radius of the shell is R, then \(\large E \times 4 \pi R^2 = \frac{Q}{\epsilon_o}\) -- leading to the formula posted above you can generalise for all radii
anonymous
  • anonymous
I understand the electric fields inside and outside the shell, but I'm having doubt only about a point on the shell, since it's a thin shell is charge Q enclosed within the Gaussian surface?
IrishBoy123
  • IrishBoy123
doesn't really matter if its thin or thick; as long as it's conducting, the charge will be at the surface so looks to me like a practical question.

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