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anonymous
 one year ago
whats the formula for factoring polynomial
anonymous
 one year ago
whats the formula for factoring polynomial

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triciaal
 one year ago
Best ResponseYou've already chosen the best response.1you basically regroup and take out common terms then use the common factor for each group essentially more common terms do you have a specific example you want to work through?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1the remainder theorem says in my words if (xa) is a factor of f(x) then when x = a the value of f(a) = 0

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1if you divide p by q and there is no remainder then q is a factor of p

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1438058403700:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you try to solve the system of elementary symmetric polynomials that make the coefficients; for a quadratic, notice: $$(xa)(xb)=x^2(a+b)x+ab$$ so in order to factor a quadratic of the form \(x^2+px+q\) we try to solve for \(a,b\) given \(p,q\): $$a+b=p\\ab=q$$

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for example, if we have \(x^2+9x+14\), we want to find \(a,b\) such that: $$a+b=9\\ab=14$$ so we could notice that \(a=2,b=7\) works giving \(x^2+9x+14=(x(2))(x(7))=(x+2)(x+7)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0normally you don't write it out, though, and instead just ask yourself mentally "what factors do I know of \(q\) that add up to \(p\)?", since: $$(x+a)(x+b)=x^2+(a+b)x+ab$$ so in \(x^2+9x+14\) we think "well, 2 and 7 make 14 and add to 9, so..."
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