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anonymous

  • one year ago

A culture started off with 5000 bacteria after 5 hours it grew too 6500 bacteria predict how many bacteria will be present after 16 hours P=Ae^kt formula

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  1. taramgrant0543664
    • one year ago
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    So you have to find k first so it started with 5000 so that's A P would be 6500 and t is 5 and you solve for k 6500=5000e^k(5)

  2. taramgrant0543664
    • one year ago
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    Once you find the k value then you can use that as k, use 5000 as A and your t would be 16 and you would solve for P

  3. anonymous
    • one year ago
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    Well how do I find out what k is?

  4. taramgrant0543664
    • one year ago
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    6500=5000e^5k 6500/5000=e^5k ln(6500/5000)=5k ln(6500/5000)/5=k

  5. anonymous
    • one year ago
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    So k would be 1.3?

  6. anonymous
    • one year ago
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    Or 0.26?

  7. taramgrant0543664
    • one year ago
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    No k=0.052 you didn't do the ln of it or divide by 5

  8. taramgrant0543664
    • one year ago
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    (ln1.3)/5=0.052

  9. taramgrant0543664
    • one year ago
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    ln is the inverse of e

  10. anonymous
    • one year ago
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    So my final equation would be p=5000e^0.052*16 ?

  11. taramgrant0543664
    • one year ago
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    Yes and solving for p is the answer you want

  12. anonymous
    • one year ago
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    Ok thanks you!(:

  13. taramgrant0543664
    • one year ago
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    No problem happy to help!

  14. anonymous
    • one year ago
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    So it seems as if my answer is wrong, what should I get for the answer?

  15. taramgrant0543664
    • one year ago
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    What did you get?

  16. anonymous
    • one year ago
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    1195.48, I don't see how I got this

  17. taramgrant0543664
    • one year ago
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    I got 11489.6

  18. anonymous
    • one year ago
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    Alright, I guess I'll just have to keep trying, thanks for the help though(:

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